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Vedmedyk [2.9K]
2 years ago
13

I'm having trouble figuring out what the equation is for the trend line and what the slope is

Mathematics
1 answer:
Talja [164]2 years ago
3 0

Answer:

The equation for the trend line would be y = -1/100x + 25

Step-by-step explanation:

In order to find the trend line, we first need to find the slope. To do so, we need to find two points on the line. The points we'll use are (0, 25) and (2500, 0). Next, we use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (0 - 25)/(2500 - 5)

m = -25/2500

m = -1/100

Now that we have this we can use the slope and the intercept in slope intercept form to model the trend line.

y = mx + b

y = -1/100x + 25

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BC = 4x + 2 AB = 8x + 8 and AC = 22 Find BC
Scilla [17]

Answer:

BC = 6.8

Step-by-step explanation:

The distance from A to B, then from B to C, is the same distance as from A to C.

Thus,

AB + BC = AC

AB = 8x + 8

BC = 4x + 2

AC = 22

AB + BC = AC

(8x + 8) + (4x + 2) = 22

Expanding the parenthesis:

8x + 8 + 4x + 2 = 22

8x + 4x + 8 + 2 = 22

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Subtracting 12 from both sides:

12x = 10

Dividing both sides by 12:

x = 10/12 = 1.2

x = 1.2

We're looking for BC. As we know,

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Let's now put in x = 1.2 into this equation:

BC = 4x + 2

BC = 4 * 1.2 + 2

Since 4 * 1.2 is 4.8:

BC = 4.8 + 2

BC = 6.8

Answer: BC = 6.8

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Can someone help with this problem
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