Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
It is A and D because as you can see it is using subtraction and multiplication and I’m sorry if I am wrong I can’t see much
Answer:
x=-2
Step-by-step explanation:
To solve this, let's set the two exponents so that they have the same base. We know that 9 is 3², so we can rewrite the left side as (3²)^(x-8), which simplifies to 3^(2x-16). Now, we have 3^(2x-16) = 3^(4x-12). Since the bases are equal, the exponents are also equal. Therefore, 2x-16 = 4x-12. When we solve, we get -2x = 4, so x=-2. Hope this helps!
All of them are correct . Number six is 0.28 as a decimal
7 x 4
-- = 28; 0.28 is the answer
25 x 4
He sold 50 lbs hope this is correct yamiyugi1234 :)
