Sam brought brushes for $8,a palette for $5,and oil paints for $15.He paid 29.82 in all.What sale-tax rate did Sam pay?

How high would you have to count before you would use the letter A in the English language spelling of a whole number?

andrew11 [14]

Would it not be one hundred and[insert number]?

7 0

3 years ago

Which of the expressions are equivalent to the one below? Check all that apply.

sdas [7]

Step-by-step explanation:

We need to find an expression that is equivalent to 4×(8+3)

We know that,

4×(8+3) = 4(11) = 44

Option (1).

(4 • 8) + 3 = 32+3 = 35. It is incorrect

Option (2).

(8 + 3) • 4 = (11) 4 = 44. It is correct.

Option (3).

4 • (3 + 8) = 4(11) = 44. It is correct.

Option (4).

4 • 8 + 4 • 3 = 32+12 = 44. It is correct.

Hence, the correct options are (2), (3) and (4).

8 0

3 years ago

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

The Widget Company is planning to produce widgets. The company has rented space for its manufacturing operation at $4,000 per mo

Helen [10]

I'll try to explain in the simplest way possible:

Total cost for a single widget: $32 + $44 = $76 for one widget.

So, since we know the cost of one widget is $76, then the price of 350 widgets would be = $76 x 350 = $26,600.

6 0

3 years ago

Reflect (10,-8) over the x-axis

cricket20 [7]

Answer:

(10,8)

Step-by-step explanation:

Symmetry over x axis: you keep x, but change the sign of y value.

So, the symmetric of (10,-8) is (10,8)

3 0

4 years ago