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notsponge [240]
3 years ago
15

ILL LITERALLY GIVE U BRAINLIEST JUST PLEASE HELP!!

Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0
J think this is right 30m>12
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Calculate the difference scores for the following data from a repeated measures study. Conduct a repeated measures t-test at apl
Delicious77 [7]

Answer:

There is no difference as per statistical evidence.

Step-by-step explanation:

We calculate t statistic from the formula

t =difference in means/Std error of difference

Here n1 = n2

t = (x bar - y bar)/sq rt of s1^2+s2^2

Let treatment I =X = 34 41 38 29

     Treatment II Y = 39 48 35 36

                     X       Y    

Mean          35.50   39.50

Variance     81.00   105.00

H0: x bar = y bar

Ha: x bar not equal to y bar

(Two tailed test at 0.05 significant level)

N1 = 4 and N2 = 4

df=N1+N2-2 = 6

s1^2 = 81/3 =27 and s2^2 = 105/3 = 35

Std error for difference =

t = -1.02

p =0.348834

p>0.05

Since p value >alpha we accept null hypothesis.

Hence there is statistical evidence to show that there is no difference in the mean level of scores.  

6 0
3 years ago
Limit (sin4x-4sinx)/x^3 when x close to zero
BartSMP [9]

\Large \boxed{\sf \bf \ \ \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}=-10 \ \  }

Step-by-step explanation:

Hello, please consider the following.

Using Maclaurin series expansion, we can find an equivalent of sin(x) in the neighbourhood of 0.

sin(x) \sim  \left(x-\dfrac{x^3}{3!}\right)\\\\\text{So, in the neighbourhood of 0}\\\\\begin{aligned}(sin(4x)-4sin(x)) &\sim \left( 4x-\dfrac{(4x)^3}{3!}-4x+\dfrac{4x^3}{3!}\right)\\\\&\sim \left(\dfrac{x^3*4*(1-4^2)}{3*2}\right)\\\\&\sim \left(\dfrac{x^3*2*(-15)}{3}\right)\\\\&\sim \left(x^3*2*(-5)\right)\\\\&\sim \left(x^3*(-10)\right)\\\end{aligned}

Then,

\displaystyle \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}\\\\= \lim_{x\rightarrow0} \ {\dfrac{-10*x^3}{x^3}}\\\\=-10

Thank you

4 0
4 years ago
Read 2 more answers
Factorise the following:<br><img src="https://tex.z-dn.net/?f=%7B3x%7D%5E%7B2%7D%20%20%2B%205x%20-%2012" id="TexFormula1" title=
Fed [463]

Answer:

(x + 3)(3x - 4)

Step-by-step explanation:

Given

3x² + 5x - 12

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 12 = - 36 and sum = + 5

The factors are + 9 and - 4

Use these factors to split the x- term

3x² + 9x - 4x - 12 ( factor first/second and third/fourth terms )

= 3x(x + 3) - 4(x + 3) ← factor out (x + 3) from each term

= (x + 3)(3x - 4)

Thus

3x² + 5x - 12 = (x + 3)(3x - 4) ← in factored form

6 0
3 years ago
On the first day it was posted online, a music video got 510 views. The number of views that the video got each day increased by
8090 [49]

Answer:

19,552 views on day 20, 114,763 views cumulative total for 20 days.

Step-by-step explanation:

The decimal equivalent to "increased by 20% per day" would be (510)*(1.20)/day, if we started with 510 views as day 0.  Day 1 would be (510)*(1.20) = 612 views.

If we have n successively days, the equation would read (510)(1.20)^n.

This means that after, lets say, 3 days, the calculation would be (510)*(1.20)^3, or 881 views.

On day 20, the calculation is (510)*(1.2)^20, or 19,552 views.

But the question asks "How many total views did the video get over the course of the first 20 days . . ?"  This seems to be asking the sum of the first 20 days, which is easy if you use a spreadsheet.  But if you read the question to mean what are the total views on day 20, the answer would be 19,552 views.

If you read the question as asking for the total sum of views over 30 days, the answer is 114,763.  Quick:  what does that amount to at $0.05 per view.

3 0
3 years ago
Find the range for the measurement of the third side of a triangle, x, given the measures of the two sides: 6 ft and 13 ft.
Rudik [331]
|13-6| < x < |13+6|

So the range will be:

7 < x < 19
8 0
3 years ago
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