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expeople1 [14]
3 years ago
6

The admission to the fair is $5 and the cost per ride is 50 cents. If his parents give hime $20, write and solve a linear equati

on to find how many rides he can go on.
Mathematics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

Step-by-step explanation:

The admission to the fair is $5 and the cost per ride is 50 cents.

Let the number of rides that he can go on be x

If one ride costs 50 cents, x rides will cost 50×x = 50x cents. Converting 50 cents to dollar, it becomes 50/100 = $0.5.

So x rides will cost $0.5x

If his parents gave him $20, he will pay $5 to be admitted into the fair. He would be left with 20- 5 = $15

The equation to find how many rides he can go on will be

0.5x = 15

Since one ride costs $0.5

x rides cost $15

x = 15/0.5 = 30

He can go on 30 rides

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Answer:

Option A.

P=73.4\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

In this problem we have a triangle with a circle inscribed in it

so

A.F=A.B\\C.B=C.D\\E.F=E.D

step 1

Find the length side B.C

C.B=A.C-A.B

substitute the given values

C.B=23-14=9\ units

step 2

Find the length side C.D

Remember that

C.D=C.B

therefore

C.D=9\ units

step 3

Find the length side E.D

we know that

E.D=E.C-C.D

substitute the given values

E.D=22.7-9=13.7\ units

step 4

Find the length side E.F

Remember that

E.F=E.D

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E.F=13.7\ units

step 5

Find the length side A.F

Remember that

A.F=A.B

therefore

A.F=14\ units

step 6

Find the perimeter

P=23+22.7+13.7+14

P=73.4\ units

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3 years ago
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