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expeople1 [14]
3 years ago
6

The admission to the fair is $5 and the cost per ride is 50 cents. If his parents give hime $20, write and solve a linear equati

on to find how many rides he can go on.
Mathematics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

Step-by-step explanation:

The admission to the fair is $5 and the cost per ride is 50 cents.

Let the number of rides that he can go on be x

If one ride costs 50 cents, x rides will cost 50×x = 50x cents. Converting 50 cents to dollar, it becomes 50/100 = $0.5.

So x rides will cost $0.5x

If his parents gave him $20, he will pay $5 to be admitted into the fair. He would be left with 20- 5 = $15

The equation to find how many rides he can go on will be

0.5x = 15

Since one ride costs $0.5

x rides cost $15

x = 15/0.5 = 30

He can go on 30 rides

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<em><u>blue</u></em><em><u> </u></em><em><u>pens</u></em><em><u>=</u></em><em><u>288</u></em>

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3 years ago
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John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
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