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vesna_86 [32]
3 years ago
11

Classify each number as rational or irrational.

Mathematics
2 answers:
zimovet [89]3 years ago
4 0
0.167\ -\ rational\\\\\dfrac{2}{9}\ -\ rational\\\\\pi\ -\ irrational\\\\\sqrt{225}=15\ -\ rational
Radda [10]3 years ago
3 0

A number is rational if we can write that number as a fraction.

A number is irrational if we can not write as a fraction. This means if a number has non repeating and non terminating decimal values then it is an irrational number.

Now let us look at our given numbers one by one.

0.167

We can write 0.167 as \frac{167}{100} . Hence it is a rational number.

\frac{2}{9} This number is already written as fraction. It is a rational number.

\pi We can not write \pi as a fraction because the equivalent   decimal values of  \pi are  non repeating and non terminating. Therefore  \pi is an irrational number. Remember that \frac{22}{7} is just an approximation for \pi. It isn't the actual value of \pi.

\sqrt225 is equivalent to 15. We can write 15 as a fraction like \frac{15}{1}. Therefore \sqrt225 is a rational number.

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Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given by:

n = 600, \pi = \frac{400}{600} = 0.6667

Hence, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 - 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6350

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 + 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6984

The 90% confidence interval is given by: (0.6350, 0.6984).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

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