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Sophie [7]
4 years ago
10

You are given two metal spheres on portable insulating stands, a glass rod, and a piece of silk.part ahow to give the spheres ex

actly equal but opposite charges?
Physics
1 answer:
stich3 [128]4 years ago
8 0
First of all, we need that the 2 spheres need to not be in contact, otherwise their charges would balance and we would have neutral spheres. Then, rub the glass rod with silk; the glass rod is then charged positively and the silk negatively. Touch one sphere with the glass rod and the other with the silk piece. Because metal spheres are excellent conductors, they will absorb all the charge and thus they will have the same charge, but opposite signs.
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Parasaurolophus was a dinosaur whose distinguishing feature was a hollow crest on the head. The 1.5-m-long hollow tube in the cr
Inessa05 [86]

Answer:

58.33 Hz

175 Hz

291.67 Hz

Explanation:

L = Length of tube = 1.5 m

v = Speed of sound in air = 350 m/s

The first resonant frequency is given by

f_1=\dfrac{v}{4L}\\\Rightarrow f_1=\dfrac{350}{4\times 1.5}\\\Rightarrow f_1=58.33\ Hz

The first resonant frequency is 58.33 Hz

The second resonant frequency is given by

f_2=3\dfrac{v}{4L}\\\Rightarrow f_2=3\dfrac{350}{4\times 1.5}\\\Rightarrow f_2=175\ Hz

The first resonant frequency is 175 Hz

The third resonant frequency is given by

f_3=5\dfrac{v}{4L}\\\Rightarrow f_3=5\dfrac{350}{4\times 1.5}\\\Rightarrow f_3=291.67\ Hz

The first resonant frequency is 291.67 Hz

8 0
4 years ago
Is it possible to stop time
finlep [7]

Answer:

NO

Explanation:

NO ES POSIBLE

8 0
3 years ago
The density of an object has the equation d = m/v. if an object has a mass of
Anit [1.1K]

Answer:

<h3>The answer is 1.92 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density  =  \frac{2.5}{1.3}  \\  = 1.923...

We have the final answer as

<h3>1.92 g/cm³</h3>

Hope this helps you

7 0
3 years ago
A loop of wire is at the edge of a region of space containing a uniform magnetic field B⃗ . The plane of the loop is perpendicul
Fantom [35]

QUESTION:

Part A

The induced emf in the loop is measured to be V. What is the magnitude B of the magnetic field that the loop was in?

Part B

For the case of a square loop of side length L being pulled out of the magnetic field with constant speed v (see the figure), what is the rate of change of area c = -\dfrac{dA}{dt}?

Answer:

Part A: B = -\dfrac{V}{c}

Part B: c=-Lv

Explanation:

Part A:

Faraday's law says that the induced voltage is equal to

V =-N \dfrac{d\Phi_B}{dt},

which in our case(because we have only one loop) becomes

V =- \dfrac{d (BA)}{dt},

and since the magnetic field is uniform (not changing),

V =-B \dfrac{dA}{dt}.

Now, we know that \dfrac{dA}{dt} =c;

therefore,

V =-B c

which gives us

\boxed{B = -\dfrac{V}{c} }

Part B:

The area of the loop can be written as

A = Lx,

where x is the instantaneous length of the side along which the loop is moving.

Taking the derivative of both sides we get:

\dfrac{dA}{dt} = -L\dfrac{dx}{dt},

and since v =\dfrac{dx}{dt} we have

c = \dfrac{dA}{dt} = -Lv

\boxed{c=-Lv}

where the negative sign indicates that the area is decreasing.

7 0
4 years ago
A 90dB sound wave strikes an eardrum whose area is 5.0×10^-5m^2. How much energy is absorbed by the eardrum per second
MakcuM [25]

-- The reference level for sound wave intensity is the threshold of human hearing, defined as  10⁻¹² W/m² .

-- This question is talking about a 90dB sound.  So its intensity is 10⁻³ W/m² .

-- The question tells us the size of the area that this sound is hitting.  So the power absorbed by that area is ...

Power = (intensity) x (area)

Power = (10⁻³ W/m²) x (5 x 10⁻⁵ m²)

Power = (10⁻³ x 5 x 10⁻⁵) W

<em>Power = 5 x 10⁻⁸ Watts</em>

(That's 5 x 10⁻⁸ Joules of energy per second.)

6 0
4 years ago
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