A current of 0. 82A flows through a light bulb. The charge passed through the light bulb during 94 s is 77.08C
The amount of charge flown for a given period of time determines the current passed through a bulb or electrical body.
The relation between the charge, current and time is given as:
Q = I × t
where, Q is the charge flown through bulb
I is the current passed through bulb
t is the time for which charge passes through bulb
Given,
I = 0.82A
t = 94s
Q = ?
Substituting the values in the above formula:
Q = I × t
Q = 0.82 × 94
Q = 77.08C
Hence, The charge passed through the light bulb during 94 s is 77.08C
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Answer:
R2 = 10.31Ω
Explanation:
For two resistors in parallel you have that the equivalent resistance is:
(1)
R1 = 13 Ω
R2 = ?
The equivalent resistance of the circuit can also be calculated by using the Ohm's law:
(2)
V: emf source voltage = 23 V
I: current = 4 A
You calculate the Req by using the equation (2):

Now, you can calculate the unknown resistor R2 by using the equation (1):

hence, the resistance of the unknown resistor is 10.31Ω
2.5 better than the first one more game to go hard but I 46 the bucks
For simplicity, let's call vector B-A vector C Then C is
Cx = (-6.1 - 2.2)
Cy = (-2.2 - (-6.9)) Or,
Cx = -8.3 Cy = 4.7
The magnitude is found with the Pythagorean theorem
||C|| = √(-8.3² + 4.7²) = 9.538