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Anton [14]
3 years ago
12

Suppose a ray of light traveling in a material with an index of refraction n a reaches an interface with a material having an in

dex of refraction n b . Which of the following statements must be true for total internal reflection to occur?
Check all that apply.A. The angle of incidence must be less than the critical angle.B. na = nbC. na > nbD. The angle of incidence must be greater than the critical angle.E. The angle of incidence must be equal to the critical angle.
Physics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer: C and D

Explanation: One of the first rule for total internal reflection to occur is that the ray must move from a dense to a less dense medium, hence refractive index of medium a must be greater than that of b.

When a ray moves from a dense to a less dense medium, the refracted ray moves away from the normal thus increasing the size of the angle of refraction (total internal refraction occurs when the angle of refraction is 90° and the angle of incidence at this point is known as the critical angle), hence the angle of incidence must be greater than the critical angle.

These points verifies option C and D

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Answer:

the force between the building and the ball is non-conservative (friction-type force)

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Which of the following weighing balances performs measurement in a closed compartment with no air currents to disturb measuremen
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Read 2 more answers
Titanium is a metal used to make golf clubs. A rectangular bar of this metal measuring 1.96 cm x 2.19 cm x 2.63 cm was found to
masha68 [24]

4.012\frac{gr}{cm^3}

Explanation

the density of an object is given by:

\text{Density(d)}=\frac{mass(m)}{\text{volume(v)}}

Step 1

find the volume of the bar

a)find the volume of the rectangular bar.

the volume of a rectangular prism is given by:

\text{Volume}=\text{ length}\cdot widht\cdot depth

replace

\begin{gathered} \text{Volume}=(\text{ 2.63}\cdot2.19\cdot1.96)(cm^3) \\ \text{Volume}=11.289012(cm^3) \end{gathered}

Step 2

now,

Let

\begin{gathered} \text{Volume}=11.289012(cm^3) \\ \text{mass}=\text{ 45.3 gr} \end{gathered}

replace in the formula

\begin{gathered} \text{Density(d)}=\frac{mass(m)}{\text{volume(v)}} \\ d=\frac{45.3\text{ gr}}{11.289012(cm^3)} \\ d=4.012\frac{gr}{cm^3} \end{gathered}

therefore, the answer is

4.012\frac{gr}{cm^3}

I hope this helps you

4 0
1 year ago
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