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Anton [14]
3 years ago
12

Suppose a ray of light traveling in a material with an index of refraction n a reaches an interface with a material having an in

dex of refraction n b . Which of the following statements must be true for total internal reflection to occur?
Check all that apply.A. The angle of incidence must be less than the critical angle.B. na = nbC. na > nbD. The angle of incidence must be greater than the critical angle.E. The angle of incidence must be equal to the critical angle.
Physics
1 answer:
KATRIN_1 [288]3 years ago
5 0

Answer: C and D

Explanation: One of the first rule for total internal reflection to occur is that the ray must move from a dense to a less dense medium, hence refractive index of medium a must be greater than that of b.

When a ray moves from a dense to a less dense medium, the refracted ray moves away from the normal thus increasing the size of the angle of refraction (total internal refraction occurs when the angle of refraction is 90° and the angle of incidence at this point is known as the critical angle), hence the angle of incidence must be greater than the critical angle.

These points verifies option C and D

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Responder:

<h2>64 Julios </h2>

Explicación:

La energía cinética se expresa mediante la fórmula KE = 1 / 2mv² donde;

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v es la velocidad del objeto

Dado que el cuerpo se mueve horizontalmente con v = 4 m / sy después de un período de tiempo se mueve con v = 20 m / s, entonces la variación en la velocidad será de 20 m / s - 4 m / s = 16 m / s.

Parámetros dados

masa del objeto m = 0,5 kg

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From the question,

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