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jekas [21]
3 years ago
12

b) When the ball is near its maximum height it experiences a brief gust of wind that reduces its horizontal velocity by 2.50 m/s

. What distance in meters does the ball travel horizontally
Physics
1 answer:
fomenos3 years ago
3 0

Answer:

The horizontal distance is 0.64 m.

Explanation:

Initial velocity, u =2.5m/s

The maximum horizontal distance is

R = \frac{u^2}{2g}\\\\R = \frac{2.5\times 2.5}{9.8}\\\\R = 0.64 m

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A 6.0-kg object, initially at rest in free space, "explodes" into three segments of equal mass. Two of these segments are observ
sladkih [1.3K]

Answer:

Q = 2000 J

Explanation:

As we know that the 6 kg object was at rest initially

So here since net force on the system is zero

so the momentum of the system will always remains conserved

so we can say

0 = P_1 + P_2 + P_3

now we know that

P_1 = P_2 = P

and the angle between the two objects is 60 degree

so we can say

\vec P_1 + \vec P_2 = \sqrt{P_1^2 + P_2^2 + 2P_1 P_2cos60}

\vec P_1 + \vec P_2 = \sqrt{P^2 + P^2 + 2P^2(0.5)} = \sqrt3 P

now we can say that the speed of the third mass will be

v_3 = \sqrt 3 (20) m/s

now the total kinetic energy released in this system is given as

Q = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2 + \frac{1}{2}mv_3^2

Q = \frac{1}{2}(2)(20^2) + \frac{1}{2}(2)(20^2) + \frac{1}{2}(2)(20\sqrt3)^2

Q = 2000 J

3 0
4 years ago
What is the acceleration of a car that maintains a constant velocity of 100km/h for 10 seconds?
dusya [7]
A constant velocity means the acceleration is zero.
6 0
3 years ago
Read 2 more answers
Biologists think that some spiders "tune" strands of their web to give enhanced response at frequencies corresponding to those a
Nat2105 [25]

Answer:

Explanation:

Given

diameter d=20 \mu m

density \rho =1300 kg/m^3

frequency \nu =150 Hz

Length of silk strand L=14 cm

Velocity in the string is as follows

\nu =\sqrt{\frac{T}{\mu }}

The expression for Fundamental Frequency

f=\frac{\nu }{2l}

f=\frac{1}{2l}\times \sqrt{\frac{T}{\mu }}

f=\frac{1}{2l}\times \sqrt{\frac{T}{\frac{m}{l}}}

f=\frac{1}{2l}\times \sqrt{\frac{Tl}{\rho V}}

Squaring

f^2=\frac{1}{4l^2}\times \frac{Tl}{\rho V}

T=4\rho \cdot A\cdot l^2\cdot f^2

T=4\times 1300\times \frac{\pi }{4}(20\times 10^{-6})^2\times (0.14)^2\times 150^2

T=7.2\times 10^{-4} N

8 0
4 years ago
How does geosphere interact with biosphere
Marina86 [1]

<span>With a partner, describe interactions in this scene, tracing the movement of materials or energy through all four of Earth's spheres if possible. Plants (biosphere) draw water (hydrosphere) and nutrients from the soil (geosphere) and release water vapor into the atmosphere.</span>
6 0
3 years ago
an object 5 cm in size is placed at 30 cm in front of a concave mirror of focal length 45 CM at what distance from the mirror sh
Makovka662 [10]

Answer: Given: h₀=5cm

p=30cm

hi

f=45cm

require: q=?

hi=?

formulas:

1/f=1/p+1/q

hi/h₀=q/p

calculations:1/q=1/f-1/p

1/q=1/45-1/30

1/q=0.022=0.033

1/q=  =    -0.011

q=1/-0.011

q=   -90.91cm

hi=p × h₀/q

hi=30ₓ5/-90.91

hi=150/-90.91

hi= -1.65cm

image is virtual , erect and diminished

please mark as brainliest plzzzzzzzzzz

3 0
3 years ago
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