Answer: Los catetos medirán 12m y 9m.
Step-by-step explanation:
Bueno, sabemos que los lados de nuestro triangulo son 6m, 8m y 10m.
Podemos usar relaciones trigonométricas para encontrar los ángulos de este triangulo.
Cos(X) = cateto adyacente/hipotenusa
Si tomamos al cateto adyacente como 8m, tenemos:
Cos(X) = 8m/10m
X = Acos(8/10)
Esto nos dice que para que nuestro otro triangulo rectángulo sea equivalente al primero, entonces los nuevos catetos C1 y C2 tienen que ser tal que los cocientes entre los catetos y la hipotenusa se mantengan constantes:
C1/15m = 8m/10m
C1 = (8/10)*15m = 12m
C2/15m = 6m/10m
C2 = (6/10)*15m = 9m.
Answer:
D. 6^-4 * 6^2
Step-by-step explanation:
= 6^-4 * 6^2
= 6 ^-2
= 1/6^2
= 1/36
Answer:
Option (C)
Step-by-step explanation:
Parent function g(x) = x² [Vertex at the origin (0, 0)]
When this function is shifted 3 units down,
Rule to be followed,
g(x) → g(x) - 3
So, g'(x) = x² - 3
Followed by 2 units shift to the left,
Rule to be followed,
g'(x) → g'(x + 2)
F(x) = (x + 2)² - 3
Therefore, Option (C) will be the answer.
Answer:
sorry I wish I could help but I'm stupid
Answer: 108336
Step-by-step explanation:
given data:
cards on deck = 52
Since 2 queens are supposed to be in the 5 card hand. Therefore, 2 queens are choosen since we have a total of 4.
Since 2 Queens have been chosen already choosen. we are left with 3cards out of the hand of 5. This cards are to be choosen from the 48 remaining cards. Similarly same process would be used for other combination of playing cards.
(42∗483)+(43∗482)+(44∗481).
= (6 * 17296) + (4 * 1128 ) + (1 * 48)
= 103776 + 4512 + 48
=108336