Answer:
<h3>Step-by-step explanation:
3, 9, 15, 21, ...
9-3 = 6; 15-9 = 6; 21-15 = 6 ⇒ d = 6
first term: a = 3
difference: d = 6
so the formula:
and:
What happens to the value of f(x)=log4x as x approaches 0 from the right
2 answers:
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Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Step-by-step explanation:
x is the hypotenuse so it means the other ones that are adjacent and opposite and you're looking for the hypotenuse so you can do c Square equals to a square + b square
