-Bubbles
-Explosion
-Pebbles
-Popping Balloon
--Hopping Noise
"javac <FILE NAME>" (unsurprisingly, stands for "java compile"), will compile your java source code in to a .java file, that can be run with the "java <FILE NAME>" command.
Make sure that your command prompt is set to the right destination when you run these commands, using "cd <DESTINATION>", otherwise they may be unable to find them in the incorrect destination.
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// function to compute sum and product
void square(int input)
{
// variable to store the square of number
long long squ_num;
calculate the square of number
squ_num=pow(input,2);
// print the output
cout<<"square of "<< input<<" is: "<<squ_num<<endl;
}
// driver function
int main()
{
int n;
// read the number until user enter 0
do{
cout<<"enter a number!! (0 to stop):";
// read the input from user
cin>>n;
// call the function to calculate square of input number
square(n);
}while(n!=0);
return 0;
}
Explanation:
Declare a variable "n" to read the input number from user.Call the function square() with parameter "n".In this function, it will calculate the square of the input number and print it.This will repeat until user enter 0 as input.Program will ends when user give 0 as input.
Output:
enter a number!! (0 to stop):5
square of 5 is: 25
enter a number!! (0 to stop):7
square of 7 is: 49
enter a number!! (0 to stop):11
square of 11 is: 121
enter a number!! (0 to stop):0
Answer:
The program to this question can be given as:
Program:
#include<iostream> //header file
using namespace std;
int main() //main method
{
int x[10],i,largest = 0,second_largest=0,n; //variable
cout << "Enter Number of elements :"; //message
cin>>n;
cout << "Insert array elements :"; //message
for(i=0;i<n;i++) //insert elements in array
{
cin >>x[i];
}
//Finding Largest element
for(i=0;i<n;i++)
{
if (x[i]>largest)
{
largest = x[i];
}
}
//finding second largset element
for(i=0;i<n;i++)
{
if (x[i]>second_largest)
{
if(x[i]==largest)
{
continue; //Ignoring largest in order to get second largest
}
second_largest=x[i];
}
}
//print value
cout <<"Largest Number:"<<largest<<endl;
cout <<"Second Largest Number:"<<second_largest;
return 0;
}
Output:
Enter Number of elements :5
Insert array elements :33
45
75
87
23
Largest Number:87
Second Largest Number:75
Explanation:
In the above program firstly we define the header file then we define the main method in the main method we define the array and other variables. We first input the number for the size of the array. Then we insert array elements after inserting array elements we search the largest number and the second largest number in the array. To search the largest number in the array we use the loop. To search the first largest number we define a condition that array is greater than the largest number and store the value into the largest variable. Then we check the second largest number in the array for this we use two conditions that are array is greater than the second largest number in this we use another condition that is array is equal to the largest number. If the inner condition is true then it will move forward and end of an inner condition. In the outer condition, the value will be stored on the second_largest variable all the conditions will be done inner the loop. At the last we print values.
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