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3 years ago

What could be the consequence of a mutation that changes the sequence of nucleotides in a promoter?

Biology

1 answer:

Korolek [52]3 years ago

4 0

Answer:

The changes in the sequence of nucleotides present within a promoter is a prime cause of the defected transcriptional regulation, which may eventually result in disease. However, not every modification within the sequence of a promoter influences the regulation of transcription, it relies upon the nature and the location of the genetic defect.

When a mutation results within the sequence of a promoter region it may hamper the usual procedures of gene stimulation by affecting the step by step alignment of the transcription factors at the promoter region. Therefore, as a consequence, a mutation within the sequence of a promoter may result in the enhancement or reduction in the level of mRNA and thus protein.

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Record your observations of how the agar cubes look before you add vinegar and then after you add vinegar and stir. How did the

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Answer:

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3 years ago

Help please! DNA Assignment

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Answer:

DNA Replication:

Replicate the following strand of DNA:

Original DNA: A T G A A C CA T T C A G T A T G G

Complementary DNA:

Remember that the complimentary base pairs in DNA are Adenine-Thymine and Guanine-Cytosine, or A-T and G-C. This means that if the original sequence is:

A T G A A C C A T T C A G T A T G G

Then the compliment is (replace with the opposite base pairs):

T A C T T G G T A A G T C A T A C C

Transcription:

Transcribe the DNA to make an mRNA molecule

COMPLIMENTARY DNA:

mRNA Molecule:

So if our complimentary DNA (antisense stand) is T A C T T G G T A A G T C A T A C C then to transcribe, we basically create another complimentary strand, but for mRNA, we use Uracil instead of Thymine:

A U G A A C C A U U C A G U A U G G

Translation:

Translate the mRNA into the corresponding amino acids.

mRNA MOLECULE:

AMINO ACID:

Using the DNA sequence provided, determine the amino acids.

Next, take each codon (3-base set) to the table and record the corresponding protein:

A U G = Methionine (start)

A A C = Asparagine

C A U = Histidine

U C A = Serine

G U A = Valine

U G G = Tryptophan

ORIGINAL DNA: A T G G G T C T A G C G A A A G A T

Complementary DNA:

mRNA DNA Molecule:

Amino Acid:

And we do it all again:

A T G G G T C T A G C G A A A G A T = original DNA

T A C C C A G A T C G C T T T C T A = complementry DNA

A U G G G U C U A G C G A A A G A U = mRNA

A U G = Methionine (start)

G G U = Glysine

C U A = Leucine

G C G = Alanine

A A A = Lysine

G A U = Aspartate

Explanation:

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3 years ago

Hypothesize how a cell would be affected if it lost the ability to be selectively permeable.

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A plant can have green (G) or yellow (g) leaves. It can also have a long (K) or short (k) stem. A scientist is preparing a Punne

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Answer: A. gk, gK

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g gK gk

The possible gamete for gg-Kk would be
1. gK
2. gk

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