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anastassius [24]
3 years ago
9

Is (-5,-5)(−5,−5)left parenthesis, minus, 5, comma, minus, 5, right parenthesis a solution of y \geq -2x +4y≥−2x+4y, is greater

than or equal to, minus, 2, x, plus, 4 ?
Choose 1 answer:
a) yes
b) no
Mathematics
2 answers:
svetoff [14.1K]3 years ago
7 0

Answer:

no

for the khan academy people

Step-by-step explanation:

julia-pushkina [17]3 years ago
6 0

Answer:

A) yes

Step-by-step explanation:

i got it correct on usatestprep

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The angle Johnny holds his pen on paper creates a linear pair. The measure of one angle is 13x + 7. The
tresset_1 [31]
<h3>The value of x is 4.10</h3>

<em><u>Solution:</u></em>

Given that,

The angle Johnny holds his pen on paper creates a linear pair

Angles in a linear pair are supplementary angles

Two angles are supplementary, when they add up to 180 degrees

The measure of one angle is 13x + 7

The  measure of the second angle is one less than twice the first angle

Therefore,

Measure of second angle = twice the first angle - 1

Measure of second angle = 2(13x + 7) - 1

Measure of second angle = 26x + 14 - 1

Measure of second angle = 26x + 13

Therefore,

Measure of first angle + measure of second angle = 180

13x + 7 + 26x + 13 = 180

39x + 20 = 180

39x = 180 - 20

39x = 160

x = 4.1

Thus value of x is 4.10

3 0
3 years ago
Please help, refer to the picture for information.
aleksklad [387]

Answer:

b

Step-by-step explanation:

Using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 1, 4) and (x₂, y₂ ) = (4, 1)

d = \sqrt{(4+1)^2+(1-4)^2}

  = \sqrt{5^2+(-3)^2}

  = \sqrt{25+9} = \sqrt{34} → b

5 0
3 years ago
Riccardo Frierson deposits $1,200 in savings account. The account pays a 3.5% annual interest rate. He makes no other deposits o
jonny [76]

Answer: 25

Step-by-step explanation:

7 0
2 years ago
Which of the following pairs of functions are inverses of each other?
natta225 [31]

Answer:

The pair which are inverse of each other are:

Option: C

f(x)=11x-4\ and\ g(x)=\dfrac{x+4}{11}

Step-by-step explanation:

Two functions f(x) and g(x) are said to be inverse of each other if:

fog(x)=gof(x)=x

i.e. the composition of two functions give identity no matter what the order is.

A)

f(x)=\dfrac{x}{12}+15 and g(x)=12x-15

Now we calculate fog(x):

fog(x)=f(g(x))\\\\fog(x)=f(12x-15)\\\\fog(x)=\dfrac{12x-15}{12}+15\\\\fog(x)=x-\dfrac{15}{12}+15\\\\fog(x)=x-\dfrac{55}{4}\neq x

Hence, option: A is incorrect.

B)

f(x)=\dfrac{3}{x}-10\ and\ g(x)=\dfrac{x+10}{2}

Now we calculate fog(x):

fog(x)=f(g(x))\\\\fog(x)=f(\dfrac{x+10}{3})\\\\fog(x)=\dfrac{3}{\dfrac{x+10}{3}}-10\\\\fog(x)=\dfrac{9}{x+10}-10\neq x

Hence, option: B is incorrect.

D)

f(x)=9+\sqrt[3]{x}\ and\ g(x)=9-x^3

Now we calculate fog(x):

fog(x)=f(g(x))\\\\fog(x)=f(9-x^3)

fog(x)=9+\sqrt[3]{9-x^3}\neq x

Hence, option: D is incorrect.

C)

f(x)=11x-4\ and\ g(x)=\dfrac{x+4}{11}

Now we calculate fog(x):

fog(x)=f(g(x))\\\\fog(x)=f(\dfrac{x+4}{11})

fog(x)=11\times (\dfrac{x+4}{11})-4\\\\fog(x)=x+4-4\\\\fog(x)=x

Similarly,

gof(x)=g(f(x))\\\\gof(x)=g(11x-4)\\\\gof(x)=\dfrac{11x-4+4}{11}\\\\gof(x)=\dfrac{11x}{11}\\\\gof(x)=x

Hence, option: C is the correct option.

6 0
3 years ago
Read 2 more answers
Can someone plz help me with 11,12,13 plz show work
dimaraw [331]

Answer:

  11.  x = -3+√37 ≈ 3.08276

  12.  x = 11.2

  13.  x = -6 +6√5 ≈ 7.41641

Step-by-step explanation:

In each case, the relation of interest is ...

  (distance to circle near) × (distance to circle far) = (distance to circle near) × (distance to circle far)

When there is only one point of intersection of the secant with the circle—because it is a tangent—then the product is the square of the length of the tangent.

11. 2(2+12) = x(x +6)

  x² +6x -28 = 0

  (x +3)² -37 = 0

  x = -3+√37 ≈ 3.08276

12. 5(5+x) = 9(9)

  5x +25 = 81

  x = 56/5 = 11.2

13. x(x +12) = 12(12)

  x² +12x -144 = 0

  (x +6)² -180 = 0

  x = -6 +√180 ≈ 7.41641

_____

<em>Comment on this secant rule</em>

This rule turns out to apply whether the point of intersection of the secant lines is outside the circle (as in these problems) or inside the circle (as in problem 9). The product of the two distances from the point of intersection to the circle is a constant for a given pair of intersecting secants/chords.

6 0
3 years ago
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