To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer:
cosa = 3/5
Step-by-step explanation:
Use Trignometrical identity cosa = √
1
−
sin
^2a
cos a = √
1
−
16
/25 = √
9
/25 = 3
/5
In this case, you aren't going to get an integer for the value of a, but you can rearrange the equation to equal a.
4a-3=D add 3 to both sides
4a=D+3 divide both sides by 4
a=(D+3)/4 here's your answer
I believe the answer is x⁢10 if it’s incorrect i’m so sorry
Answer:
x = 5 and -2
Step-by-step explanation:
Given the function of x to be;
f(x) = (x-5)(x+2)/x+1
The value of x that will make the function zero can be calculated for by equating the given function to zero first to have;
If f(x) = 0, then;
(x-5)(x+2)/x+1 = 0
Cross multiplying;
(x-5)(x+2) = 0
(x-5) = 0 and x+2 = 0
x = 5 and x = -2
The value of x that will make the function zero is therefore 5 and -2
