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Levart [38]
3 years ago
14

Could any kind person help me with this equation please

Mathematics
1 answer:
kondor19780726 [428]3 years ago
5 0

M’ (-4, 7)

N’ (0, 5)

P’ (2, 0)

Q’ (-2, 1)

you basically change the x and y values by the value it says so you'd subtract 4 from x (the first number) and add 1 to y (the second number)

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Answer:

\dfrac{x}{3}+\dfrac{3}{y}

Step-by-step explanation:

<u>Given fraction</u>:

\dfrac{xy+9}{3y}

\textsf{Apply the fraction rule} \quad \dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}:

\implies \dfrac{xy}{3y}+\dfrac{9}{3y}

Rewrite 9 as 3 · 3:

\implies \dfrac{xy}{3y}+\dfrac{3 \cdot 3}{3y}

Cancel the common factor y in the first fraction and the common factor 3 in the second fraction:

\implies \dfrac{x\diagup\!\!\!\!y}{3\diagup\!\!\!\!y}+\dfrac{\diagup\!\!\!\!3 \cdot 3}{\diagup\!\!\!\!3y}

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