Question

(a^2 - b^2)/(2 + d^3)

Answer 1

Answer:

Solving the equation $\frac{a^2-b^2}{2+d^3}$ by putting a=6, b=4 and d=1/2 we get $\frac{160}{17}$

Step-by-step explanation:

We are given formula: $\frac{a^2-b^2}{2+d^3}$

and values a=6, b=4 and d=1/2

We need to put the values of a, b and d in the given equation $\frac{a^2-b^2}{2+d^3}$ and find their result

Putting values in the equation:

$\frac{a^2-b^2}{2+d^3}\\=\frac{(6)^2-(4)^2}{2+(\frac{1}{2})^3}\\=\frac{36-16}{2+\frac{1}{8}}\\=\frac{20}{\frac{2*8+1}{8}}\\=\frac{20}{\frac{17}{8}}\\=\frac{20*8}{17}\\=\frac{160}{17}$

So, solving the equation $\frac{a^2-b^2}{2+d^3}$ by putting a=6, b=4 and d=1/2 we get $\frac{160}{17}$