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Zarrin [17]
3 years ago
11

Vi walks five days each week.She walks the same distance on the first two days.On days three and four,Vi walks twice as long as

on the first two days.On day five she walks half as far as on day 1.If Vi walks 13 miles each week how does she walk each day
Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Vi walks 2 miles on first day, 2 miles on second day, 8 miles on third and fourth day and 1 mile on fifth day.

Step-by-step explanation:

Let,

x be the distance walked by Vi.

Therefore,

On first day = x

Second day = x

On days three and four,Vi walks twice as long as on the first two days

Third and fourth day = 2(x+x) = 2(2x) = 4x

On fifth day = half of first day = \frac{1}{2}x = 0.5x

Total distance = 13 miles

Therefore,

x+x+4x+0.5x =13\\6.5x=13

Dividing both sides by 6.5

\frac{6.5x}{6.5}=\frac{13}{6.5}\\x=2

Distance on first day = x = 2 miles

second day = x = 2 miles

third and fourth day = 4x = 4(2) = 8 miles

fifth day = 0.5x = 0.5(2) = 1 miles

Vi walks 2 miles on first day, 2 miles on second day, 8 miles on third and fourth day and 1 mile on fifth day.

Keywords: distance, addition

Learn more about distance at:

  • brainly.com/question/9323337
  • brainly.com/question/9381080

#LearnwithBrainly

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Answer:

w = 5

Step-by-step explanation:

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2 years ago
For a school play, 739 tickets valued at $857 were sold. Some cost $1 and others cost a $1.50. How many $1 tickets were sold?
balu736 [363]

Answer:

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Step-by-step explanation:

Use two equations  

Let x = number of $1 tickets sold  

Let y = number of $1.50 tickets sold  

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Plug this into the second equation  

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