<span>Raduis of Can=1/2 of 12cm</span>
<span><span>R=6cm
</span></span>
<span>
</span>
<span>Volume of Can= pi r ^{2} h</span>
<span /><span><span>= pi 6 ^{2} 16</span></span>
<span><span />=1809.5573cm3</span>
<span /><span>
</span>
<span>Volume of Meatball=4/3 pi r ^{3}</span>
<span /><span>=4/3 pi 3 ^{3}</span>
<span>=113.09734</span>
<span>
</span>
<span>25% of can =</span>
<span>1809.5573/4</span>
<span>=452.389325</span>
<span>Meatballs in area = 25%of can/volume of meatballs</span>
<span>=452.389325/113.09734</span>
<span>=4 meatballs</span>
Answer: 
Step-by-step explanation:
m=
=
Since x³ = x^(1/3) you can say that
(x¹⁰)^(1/3) = x^10/3 = x^(3 + 1/3) =
x³ ·∛x
Team B because mode is how often a number appears in a list and 60 is greater than 48 or 30, which are the modes of Team A and Team C
Hope this helps!
Graph C is the correct option.
If you drew a straight line (mostly) connecting the points, it would be linear. A relationship is linear if one variable, in this case, x, increases by approximately the same rate as the other variables, in this case y.
If you drew lines connecting points on the other graphs, they wouldn’t resemble a straight line, therefore, they aren’t linear.
