Hey! So, here's a tip. When writing exponents, an easier way is to write a^b, rather than a to the b power. Besides that, here is your answer!

So-------

9^3=729

3^2=9

6^3=216

15^2=225

Now that we have that figured out, we can add them together, wish is simple. 729 + 9 + 216 + 225= 1,179.

Therefore, your final answer will be 1,174.

If you have any questions on this, I'm happy to help you. :)

5 0

3 years ago

What is the volume, in cubic feet, of a cone that has a base area of π / 4 square feet and a height of 3 feet?

rewona [7]

$The\ volume\ of\ a\ cone:V=\frac{1}{3}B\cdot H\\\\B=\frac{\pi}{4}ft;\ H=3ft\\\\therefore\\\\V=\frac{1}{3}\cdot\frac{\pi}{4}\cdot3=\boxed{\frac{\pi}{4}\ (ft^2)=\frac{1}{4}\pi\ (ft^2)}$

8 0

4 years ago

Hi :) how to do question 7 ?

Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= $\frac{-3}{2}$ x+8
We khow that the points P and Q are two points in the cercle
Let Ω be the center of this cercle
we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
PΩ= $\sqrt{(a-4)^{2}+(b-6)^{2} }$ and QΩ= $\sqrt{(a-8)^{2}+(b-2)^{2} }$
Let's substitute a by x and b by y
PΩ=QΩ we substitute each distance by its expression
After simplyfying the expressions we get finally : -12+8x-8y=0
now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
we substitute a by 4 and y by 2 in PΩ to get the radius
we get r = $\sqrt{(4-4)^{2}+(2-6)^{2} }$ = 4
so r²= 16
then the equation is : (x-4)²+(y-2)²=16

5 0

3 years ago

Read 2 more answers

The distance d (in feet) that it

Marta_Voda [28]

Answer:

40 mph

Step-by-step explanation:

To find the maximum speed at which the car can travel, as the distance it requires to stop is 168 feet, we just need to use the value of d = 168 in the equation, and then find the value of s:

168 = 0.05s^2 + 2.2s

0.05s^2 + 2.2s - 168 = 0

Using Bhaskara's formula: we have:

Delta = 2.2^2 + 4*0.05*168 = 38.44

sqrt(Delta) = 6.2

s1 = (-2.2 + 6.2)/0.1 = 40 mph

s2 = (-2.2 - 6.2)/0.1 = -84 mph (a negative value does not make sense as 's' is the speed of the car)

So the maximum speed of the car is 40 mph

3 0

3 years ago