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Alexus [3.1K]
3 years ago
14

Point M begins at (5,-2). Write the coordinates of Ry= 1 (M). Is this correctly illustrated

Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

No

Step-by-step explanation:

The reflection (R) around the line y = 1 is not the point illustrated.

Notice that the original point M (5,-2) is THREE (3) units below the line y=1, therefore when doing the reflection, it should end up THREE units above the y=1 line.

That is, it should end up at the point (5,4 ) and not at (5,3) as is shown in the picture.

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Find the equation of the line through point (1,−5) and perpendicular to y=1/8x+2. Use a forward slash (i.e. "/") for fractions (
Masteriza [31]

Answer:

y = -8x + 3

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept.

Perpendicular lines:

When two lines are perpendicular, the multiplication of their slopes is -1.

Perpendicular to y=1/8x+2

This line has slope \frac{1}{8}

So, for the line we want to find the equation, we have that:

\frac{m}{8} = -1

m = -8

So

y = -8x + b

Find the equation of the line through point (1,−5)

This means that when x = 1, y = -5. We use this to find b. So:

y = -8x + b

-5 = -8 + b

b = 3

The equation of the line is:

y = -8x + 3

7 0
3 years ago
-(2x-3)+x=1/3(4x+5)-8
alexira [117]

I wrote my decision on a piece of paper.

6 0
3 years ago
The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.
Scrat [10]

Just did a specific one of these; let's do the general case.


The point nearest the origin is (a,b).


The line from the origin through the point is


bx - ay = 0


The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):


ax + by = a^2 + b^2


ax + by -( a^2 + b^2) = 0


That's standard form; let's plug in the numbers:


4 x - 4 y - 32 = 0


x - y - 8 = 0



5 0
3 years ago
What is the lowest value of the range of the function
Rasek [7]

The question is incomplete. Below you will find the missing graph.

The lowest value of the range of the function shown on graph is (B) -2.

Graph is the pictorial representation of the function or mathematical relation.

The lowest value of the graph is the value of y when y=f(x) gives the least value.

From the given graph we can clearly see that at x=3 the graph of the given function approaches the least value which is -2.

So the lowest value of the range of the function shown on the graph is -2.

Hence the correct option is (B).

Learn more about Graph here -

brainly.com/question/4025726

#SPJ10

7 0
2 years ago
(x-1)^2+(2-x)^2-3(x-5)*(x-5)
Natali5045456 [20]

Answer:

-x^2+24x-70

Step-by-step explanation:

(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5  - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70

Formula used =

(a-b)^2 = a^2+ 2ab + b^2

8 0
2 years ago
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