If there's a plus sign in between the 2w and 3 then the answer is C. w 5.5
Your answer should be 120
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
Force, F = 68.93 pounds
Step-by-step explanation:
Given that,
Mass of the astronaut, m = 80.70 kg
Acceleration due to gravity on Mars, 
The force acting on him is given by using second law of motion as :
F = 306.66 N
Since, 1 newton = 0.224 pound
F = 306.66 N = 68.93 pounds
So, 68.93 pounds force she exerts on the martian surface. Hence, this is the required solution.
