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Elena L [17]
3 years ago
15

What is the common ratio of the associated geometric sequence

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
4 0

Answer:

The geometric series 3, 6, 12, 24, 48, . . . has common ratio r = 2.

Step-by-step explanation:

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Give the degree and classify the polynomial by the number of terms.
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degree 3, binomial

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Twice the sum of a number and 10 is -20
Reptile [31]
Let, the number = x

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Solve this equation 8-x2= -17
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A recent study examined hearing loss data for 1981 U.S. teenagers. In this sample, 369 were found to have some level of hearing
ruslelena [56]

Answer:

There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.

P-value=0.12

Step-by-step explanation:

We have to perform a test of hypothesis on the proportion.

The claim is that the proportion of US teens that have some level of hearing loss differs from 20%.

Then, the null and alternative hypothesis are:

H_0: \pi=0.20\\\\H_a:\pi\neq0.20

The significance level is assumed to be 0.05.

The sample, of size n=1981, has 369 positive cases. Then, the proportion is:

p=X/n=369/1981=0.186

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.2*0.8}{1981}}=\sqrt{ 0.000081 }= 0.009

Now, we can calculate the statistic z:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.186-0.20+0.5/1981}{0.009}=\dfrac{-0.014}{0.009}=-1.556

The P-value for this two-tailed test is:

P-value=2*P(z

The P-value is below the significance level, so the effect is not significant. The null hypothesis failed to be rejected.

There is no enough evidence to support the claim that the proportion of US teens that have some level of hearing loss differs from 20%.

7 0
3 years ago
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