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azamat
3 years ago
15

Dodge, Incorporated acquires 15% of Gates Corporation on January 1, 2013, for $105,000 when the book value of Gates was $600,000

. During 2013 Gates reported net income of $150,000 and paid dividends of $50,000. On January 1, 2014, Dodge purchased an additional 25% of Gates for $200,000. Any excess cost over book value is attributable to goodwill with an indefinite life. The fair-value method was used during 2013 but Dodge has deemed it necessary to change to the equity method after the second purchase. During 2014 Gates reported net income of $200,000 and reported dividends of $75,000.
1. Which adjustment would be made to change from the fair-value method to the equity method?
Business
1 answer:
nata0808 [166]3 years ago
8 0

Answer:

Goodwill    35,000 debit

   Investment in Gates      25,000 credit

  Retained Earnings          10,000 credit

--to adjust for change of method--

Explanation:

600,000 x 15% = 90,000

purchased at     105,000

<em>goodwill of 15,000</em>

<em />

+ 150,000 x 15% of net income = 22,500

- 50,000 x 15% dividends          =   (7,500)

<em>investment at the end of 2013:</em>

90,000 + 22,500 - 7,500 = 105,000

Then we purchase 25%

105,000 represent 15%

thus 25% would be: 105,000 / 0.15 x 0.25 = 175,000

purchased at 200,000

goodwill of 25,000 to be recognized.

So, equity method will be:

105,000 + 175,000 = 280,000 for the proportional equity

and 15,000 + 25,000 = 35,000 goodwill

Total of 315,000

While fair value will not recognize goodwill. and also, the investment is not modified when dividends and the gain for the year are delcared.

It measure at cost unless the market value of the stock decrease so we got:

105,000 1st purchase + 200,000 2nd purchase = 305,000

To adjust we are going to decrease investment by 25,000 and increase goodwill by 35,000 the other will go into retained earnings to balance out.

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<h3>The short-run aggregate supply curve shows the relationship between the price level and aggregate expenditure </h3>

Explanation:

A short-run aggregate supply curve (SRAS) is a graphical model that shows the positive relationship between aggregate price level and aggregate production amount supplied in an economy. The short-run aggregate supply curve is sloping upward as the supplied quantity increases as the prices increase.

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The Shirt Shop had the following transactions for T-shirts for Year 1, its first year of operations: Jan. 20 Purchased 400 units
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Answer:

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FIFO  2,260

Explanation:

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We add the units purchase and the subtotal to get the total units available for sale.

Ending inventory physical units: 970 - 810 = 160 units

<u>Then, we calculate for each method:</u>

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LIFO:

Ending inventory will be the oldest units:

160 units x 8 = 960

FIFO:

Ending inventory will be the newest units as the units are sold as soon as they come in

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A broad principle that requires identifying the activities of a business with specific time periods such as months, quarters, or
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Any company's financial statements can be thought of as a snapshot in time that reveals both the company's history and its current status. That's why it's crucial to disclose to readers the time frame in which the financial statements were generated in accordance with the time period concept.

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3 0
1 year ago
A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius
anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

T^2 \alpha  a^3

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 \times 10^8 \ km

Therefore, T^2 = ca^3

c= \dfrac{365^2}{(1.496 \times 10^8)^3}

c = 3.9791 \times 10^{20} \ day^2/km^3

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

T^2 = ca^3

a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}

a^3 = 2.9092 \times 10^{27}

a= \sqrt[3]{2.9092 \times 10^{27}}

a = 1.4275 \times 10^9 \ km

However, the velocity for a perihelion = 10.18 km/s

Using the formula

v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})} to calculate the radius, we have:

G = 6.674 \times 10^{-11}

M = 1.989\times 10^{30} \ kg

r = perihelion

v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})

(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30}  ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})

7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}

\dfrac{2}{r} = 1.4824 \times 10^{-12}

r = \dfrac{2}{1.4824 \times 10^{-12}}

r = 1.349 \times 10^{12}

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)

1.349 \times 10^{12}  -  1.425 \times 10^{12}= -  1.425 \times 10^{12} (e)

-7.6\times 10^{10}= -  1.425 \times 10^{12} (e)

\dfrac{-7.6\times 10^{10}}{-  1.425 \times 10^{12}}=  (e)

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

r = 1.425 \times 10^{12} ( 1 + 0.0533)

r = 1.50 \times 10^{12} \ m

to nautical miles, we have:

r = 1.50 \times 10^{12} \times 0.00054  \ nautical \ mile

radius of aphelion \mathbf{r = 8.10 \times 10^8} nautical miles

In respect to the value of a( i.e 1.4275 \times  10^9 \ km)

the body of the solar system is Saturn

5 0
3 years ago
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