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2 years ago

How many complete pieces of ribbon 7/8cm long can be cut from a roll of ribbin that is 149 cm long

Mathematics

2 answers:

ICE Princess25 [194]2 years ago

7 0

129 to 130 pieces is the answer

user100 [1]2 years ago

6 0

$\frac{1192}{7}$
Convert 149 to a fraction ( $\frac{149}{1}$ ).
To divide by a fraction, use the inverse or reciprocal (switch the numerator and denimoninator).
The reciprocal of $\frac{7}{8} [tex] is [tex] \frac{8}{7}$ .
So, multiply those two fractions together (149 x 8 = 1192) (1 x 7 = 7) to get $\frac{1192}{7}$

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Help for most brain! lol

Juliette [100K]

Answer:

Im pretty sure it's false because 7.4p could 74, 148, 222 or 296. so it would be the other way around. It's false.

Step-by-step explanation:

7 0

2 years ago

In a 3-digit number, the hundreds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the s

MaRussiya [10]

Answer:

The mentioned number in the exercise is:

362

Step-by-step explanation:

To obtain the mentioned number in the exercise, first you must write the equations you can obtain with it.

If:

x = hundredths digit
y = tens digit
z = ones digit

We can write:

x = z + 1 (the hundreds digit is one more than the ones digit).
y = 2x (the tens digit is twice the hundreds digit).
x + y + z = 11 (the sum of the digits is 11).

Taking into account these data, we can use the third equation and replace it to obtain the number and the value of each digit:

x + y + z = 11
(z + 1) + y + z = 11 (remember x = z + 1)
z + 1 + y + z = 11
z + z +y + 1 = 11 (we just ordered the equation)
2z + y + 1 = 11 (z + z = 2z)
2z + y = 11 - 1 (we passed the +1 to the other side of the equality to subtract)
2z + y = 10
2z + (2x) = 10 (remember y = 2x)
2z + 2x = 10
2z + 2(z + 1) = 10 (x = z + 1 again)
2z + 2z + 2 = 10
4z + 2 = 10
4z = 10 - 2
4z = 8
z = 8/4
z = 2

Now, we know z (the ones digit) is 2, we can use the first equation to obtain the value of x:

x = z + 1
x = 2 + 1
x = 3

And we'll use the second equation to obtain the value of y (the tens digit):

y = 2x
y = 2(3)
y = 6

Organizing the digits, we obtain the number:

Number = xyz
Number = 362

As you can see, the obtained number is 362.

8 0

3 years ago

The net of a rectangular prism is shown below. What is the total surface area of the prism in square centimeters?

goldfiish [28.3K]

Answer:

B.96

Step-by-step explanation:

7 0

2 years ago

What is the simplified form of the following expression? Assume a greater-than-or-equal-to 0 and c greater-than-or-equal-to 0

Setler [38]

Answer:

A. 7ac(^4sqrt. ab^2)

Step-by-step explanation:

just took the quiz on edg.

3 0

3 years ago

A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately 2020.022

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

$\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}$

Therefore, for the last term we have;

$\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}$

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

$\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}$

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)$

Which gives;

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)$

$\displaystyle A = 2 \times 1011 \cdot \left(1 - \frac{1}{2022} \right) = \frac{1032231}{511} \approx \mathbf{2020.022}$

A ≈ 2020.022

Learn more about the sum of a series here:

brainly.com/question/190295

8 0

2 years ago

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