Question

Which option is correct and how would one solve for it?

Answer 1

Answer:

28

Step-by-step explanation:

We need to find the value of $\Sigma_{x=0}^3\ 2x^2$

We know that,

$\Sigma n^2=\dfrac{n(n+1)(2n+1)}{6}$

Here, n = 3

So,

$\Sigma n^2=\dfrac{3(3+1)(2(3)+1)}{6}\\\\\Sigma n^2=14$

So,

$\Sigma_{x=0}^3\ 2x^2=2\times 14\\\\=28$

So, the value of $\Sigma_{x=0}^3\ 2x^2$ is 28. Hence, the correct option is (d).