Answer:
The beam will bend by 50 mm with a mass of 100kg?
Step-by-step explanation:
The first step in solving the problem of direct variation is setting up the relation mathematically.
We can do this as follows:
The bending of the beam varies directly as its mass.
here is the symbol representing direct variation. To remove this and replace it with an equality sign, we have to introduce a constant of proportionality, k
k = 20 /40 = 0.5
We can now use this to find the distance the beam will bend with a mass of 100kg?
This will be
There fore, the beam will bend by 50 mm with a mass of 100kg?
Well 33 is rounded down to 30
And 89 is rounded up to 90
So it would be 120
Anything from 1-4 is rounded down and anything 5-9 is rounded up
Answer:
its the quotient of
Step-by-step explanation:
10/3= 3.333 and so on
Answer:
See below
Step-by-step explanation:
The first two questions are slope = 0
a horizontal line has zero slope
slope = rise/run = 0 / run = 0
Greatest y value is + 4 from x = 3 to 4
the least y value is -3 fro x = -4 to -3
Answer:
KL = 27
JK = 16
MK = 30
NL = 23
m∠JKL = 132°
m∠KLJ = 22°
m∠KMJ = 54°
m∠KJL = 26°
Step-by-step explanation:
The given parameters of the quadrilateral JKLM are;
JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22
Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram
Therefore;
KL = JM = 27
JK = ML = 16
m∠KLJ = m∠MJL = 22°
MN = NK = 15
MK = MN + NK = 15 + 15 = 30
NL = JL/2 = 46/2 = 23
m∠KJM = m∠KLM = 48°
m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°
m∠KML = m∠JKM = 78°
m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°
m∠MKL = 54°
m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°
m∠KMJ = m∠MKL = 54°
