Solving this problem needs the distance formula of point to a line.
The formula is:
distance = | a x + b y + c | / √ (a^2 + b^2)
So we are given the equation: y = 2 x + 4
Rewriting this would be: y – 2 x – 4 = 0 -> a = -2, b = 1, c = -4
We are also given the points:
(-4, 11) = (x, y)
Plugging it in the distance formula at points (x, y):
distance = | -2 * -4 + 1 * 11 + -4 | / √ [(- 2)^2 + (1)^2]
= 15 / √ (5)
= 6.7
So the tree is approximately 6.7 feet away from the zip line.
Answer:
f(x) = (x - 3)(x + 1) → Corresponds with the first (raised higher ) ∪ shaped graph
f(x) = -2(x - 1)((x + 3) → Corresponds with the ∩ shaped graph
f(x) = 0.5(x - 6)((x + 2) → Corresponds with the second (lower) ∪ shaped graph
Step-by-step explanation:
For the function f(x) = (x - 3)(x + 1)
We have;
When x = 0, y = -3
When y = 0 x = 3 or -1
Comparing with the graphs, it best suits the first ∪ shaped graph that rises here than the other ∪ shaped graph
For the function;
f(x) = -2(x - 1)((x + 3)
When x = 0, y = 6
When y = 0, x = 1 or -3
Which corresponds with the ∩ shaped graph
For the function;
f(x) = 2(x + 6)((x - 2)
When x = 0, y = -24
When y = 0, x = -6 or 2
Graph not included
For the function;
f(x) = 0.5(x - 6)((x + 2)
When x = 0, y = -6
When y = 0, x = 6 or -2
Which best suits the second ∪ shaped graph that is lower than the other (first) ∪ shaped graph
For the function;
f(x) = 0.5(x + 6)((x - 2)
When x = 0, y = -6
When y = 0, x = -6 or 2
Graph not included
For the function;
f(x) = (x + 3)((x - 1)
When x = 0, y = -3
When y = 0, x = -3 or 1
Graph not included
Answer:
The graph is shifted right by 9 units and down by 3 units
Step-by-step explanation: