There are 3 consecutive integers such that the sum of the 2 smallest integers is 17 less than three times the largest. What is t
he smallest integer
1 answer:
Answer:
X + (X+1) +(X+2)
(X+(X+1)) = 3 *(X+2) + 17
2X +1 = 3X + 6 +17
X = -22
So the three integers are -22 -21 and -20
Double-Check *******************
(-22 -21) = 3 * (-20)
-43 = -60 +17
Step-by-step explanation:
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