Question

There are 3 consecutive integers such that the sum of the 2 smallest integers is 17 less than three times the largest. What is the smallest integer

Answer 1

Answer:

X + (X+1) +(X+2)

(X+(X+1))  = 3 *(X+2) + 17

2X +1 = 3X + 6 +17

X = -22

So the three integers are -22 -21 and -20

Double-Check *******************

(-22 -21) = 3 * (-20)

-43 = -60 +17

Step-by-step explanation: