8. A length of rope measures 5/8 of a yard long. Rylan would like to cut it into two equal portions.

NISA [10]

1. Using your straightedge, draw a reference line, if one is not provided.
2. Copy the side of the square onto the reference line, starting at a point labeled A'.
3. Construct a perpendicular at point B' to the line through ab2.
4. Place your compass point at B', and copy the side of the square onto the perpendicular b'g. Label the end of the segment copy as point C.
5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.

4 0

2 years ago

a) What is the probability that a person selected at random from the general population is senior citizen who will get the flu t

Greeley [361]

<span>The probability that a person selected at random from the general population is senior citizen who will get the flu this season is 0.14 x 0.18 = 0.0252</span>

7 0

3 years ago

Which is equivalent to

Kitty [74]

Answer:

2^2 your welcome

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Omar saved the same amount of

xz_007 [3.2K]

Answer:

Omar saved 10 dollars in total

Step-by-step explanation:

total= 2.5*4

total= $10

3 0

2 years ago

A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A

Nikitich [7]

Answer:

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where $\mu=2.5$ and $\sigma=1.7$

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And for this case the standard error would be:

$\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where $\mu=2.5$ and $\sigma=1.7$

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And for this case the standard error would be:

$\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125$

6 0

3 years ago