Answer:
D. XHxh and XHY
Explanation:
since this is the only answer with genes that share a common allele, the answer is D.
In order for a recessive gene to be present, the daughter must have gained the alleles of XHXH, which in this case, is a 25% chance. The other two possibilites are XHxh, XHY, and Yxh. To further prove this, a female must have 2 X alleles and to have hemophilia, they must carry 2 H's. If they were to only have one H, they would be a carrier instead of a product.
