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swat32
2 years ago
5

Tony started his math project at 1{:}57\text { p.m.}1:57 p.m.1, colon, 57, space, p, point, m, point and finished the project 80

8080 minutes later. Tony has band practice at 4{:}00\text{ p.m.}4:00 p.m.4, colon, 00, space, p, point, m, point
How much time did Tony have between the end of the project and the beginning of band m ?
Mathematics
2 answers:
prisoha [69]2 years ago
6 0

Answer:

43 minutes

Step-by-step explanation:

MakcuM [25]2 years ago
6 0

Answer:

43 min

Step-by-step explanation:

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Plans Math Fourth grade > W.4 Parallel sides in quadrilaterals 58M How many pairs of opposite sides are parallel? no pairs 1
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2 pairs

Step-by-step explanation:

The north & south sides are parallel and the east & west are parallel.

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The distance between Columbus,Ohio and New York City is about 560 miles how many hours would it take the train to travel between
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Since the distance is 560 miles and the bus goes 268 miles per hour, the answer can be given as:
If 268=1 hour
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560/268*1 hour =2(rounded to nearest ones)
Therefore it will take the train approximately 2 hours to travel between both cities.
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3 years ago
In the right triangle shown m
GREYUIT [131]
I needa see it tho for I could help
8 0
3 years ago
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A baseball is thrown into the air from the top of a 224-foot tall building. The baseball's approximate height over time can be r
lianna [129]
H(t) = 0 for t = 7 and for t = -2.

It is reasonable for the time to be positive, 7 seconds.

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<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
2 years ago
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