Need assistance please thanks.

A pasture is twice as long as it is wide. its area is 88,200 ft2. how wide is the pasture?

OLga [1]

If the width is w and the length is l, then 2w=l. In addition, l*w=88200 (using the area formula). Plugging 2w in for l, we get 2w*w=88200=2w^2. Dividing both sides by 2, we get w^2=44100 and w=sqrt(44100)=210.

4 0

3 years ago

There are exactly 1,944 of the 12-, or 0.5-, cubes inside a rectangular prism.

drek231 [11]

The volume of the rectangular prism is 3359232 cubic centimeters

<h3>How to determine the volume?</h3>

The length of the cube is given as:

Length, l = 12 cm

The volume of a cube is:

$V = l^3$

So, we have:

$V = 12^3$

Evaluate

V = 1728

The volume of 1944 cubes is then calculated as:

Volume = 1728 * 1944

Evaluate

Volume = 3359232

Hence, the volume of the rectangular prism is 3359232 cubic centimeters

Read more about volumes at:

brainly.com/question/1972490

#SPJ1

<h3>Complete question</h3>

There are exactly 1,944 of the 12 cm, or 0.5 foot cubes inside a rectangular prism. What is the volume of the rectangular prism in cubic centimeters?

7 0

2 years ago

Marcus drew a quadrilateral with only 1 pair of parallel sides. Which quadrilateral did Marcus draw? parallelogram rhombus trape

SpyIntel [72]

Answer:

Trapezoid

Step-by-step explanation:

We have been given that Marcus drew a quadrilateral with only 1 pair of parallel sides. We are asked to determine the quadrilateral that Marcus drew.

We know that a parallelogram has two pair of parallel sides.

We also know that rhombus is a parallelogram whose 4 sides are equal is measure and rectangle is a parallelogram with opposite sides equal.

Since parallelogram, rhombus and rectangle has two pair of parallel sides, therefore, Marcus didn't draw any of these.

We know that trapezoid has only one pair of parallel sides, therefore, Marcus drew a trapezoid.

8 0

3 years ago

Hi please help me thanksss<br>pls provide workings too thanks :)

anygoal [31]

Step-by-step explanation:

Search for questions & chapters

Class 11

>>Maths

>>Trigonometric Functions

>>Trigonometric Equations

>>Solve for x: sin x + sin 2x...

Question

Bookmark

Solve for x:sinx+sin2x+sin3x=cosx+cos2x+cos3x in the interval 0≤x≤2π.

Medium

Solution

verified

Verified by Toppr

We write the given equation as

(sinx+sin3x)+sin2x=(cosx+cos3x)+cos2x

or 2sin2xcosx+sin2x=2cos2xcosx+cos2x

or sin2x(2cosx+1)=cos2x(2cosx+1)

or (sin2x−cos2x)(2cosx+1)=0

∴sin2x−cos2x=0 or 2cosx+1=0

If sin2x−cos2x=0, then tan2x=1,

Hence 2x=nπ+π/4

or x=(4n+1)

8

π

.(1)

If 2cosx+1=0, then cosx=−1/2 (2)

∴x=2nπ±

3

2π

or x=

3

6n±2

π

We seek values of x in the interval 0≤x≤2π

In this interval (1) gives

x=π/8,5π/8,9π/8,13π/8. (n=0,1,2,3)

and (2) gives x=2π/3,4π/3. (for n=0,1)

Thus we get the answer

x=π/8,5π/8,2π/3,9π/8,4π/3,13π/8.

4 0

2 years ago

How does this graph change between point D and point G?

Leona [35]

Answer:

i don't see the graph

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers