The estimate of the population proportion of defectives is 0.05.
Given that,
There are 10 different samples of 50 observations, that is, total of 500 observations.
To find : The estimate of the population proportion of defectives
And total number of defectives from 500 observations is (5+1+1+2+3+3+1+4+2+3) = 25
Thus, the point estimate for the population proportion defectives will be,
=25/500=0.05
or just obtain the individual proportion of each sample and then take their average to obtain the same result.
Thus, the point estimate for the population proportion defectives will be 0.05
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Answer: pls mark me brainiest
Step-by-step explanation:
I am very sure that the answer is V≈351.86
Answer:as likely as not
Step-by-step explanation:
Answer: 12.25
Step-by-step explanation:
Given the following details :
DAC = 90° and ABC = 90° = right angled
Segment AB is Parallel to segment DC
FROM THE DETAILS ;
Triangle ABC and ACD are similar triangles.
Length AC = 7 Units
Length AB = 4 Units
For similar triangles :
Segment CD /AC = Segment AC / AB
CD / 7 = 7 / 4
Cross multiply
CD × 4 = 7 × 7
CD × 4 = 49
CD = 49 / 4
CD = 12.25 Units
