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3 years ago

Please help me please

Mathematics

2 answers:

alexdok [17]3 years ago

8 0

Answer: m =60

Step-by-step explanation:

bulgar [2K]3 years ago

5 0

Thanks
for you points have a great life and good luck!

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The product of 12 and y increased by 11

GenaCL600 [577]

12*(y+11) is 12y+132.

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3 years ago

Read 2 more answers

I really need help again.

REY [17]

Answer:

Y = -1/2X +4

Step-by-step explanation:

x1 y1 x2 y2

2 3 0 4

(Y2-Y1) (4)-(3)= 1 ΔY 1

(X2-X1) (0)-(2)= -2 ΔX -2

slope= - 1/2

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Y =-0.5X +4

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3 years ago

Find the area of the shaded region. Need a Hint? 40 square meters 23 square meters 56 square meters 12.5 square meters

sesenic [268]

<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any diagram so I'll assume we are talking about a square. If so, then the area of the square is given by:

$A=s^2 \\ \\ s:Side \ of \ the \ square$

From the figure below, we know that the side of the square is:

$s=20m$

So the area can be found as:

$A=(\sqrt{40})^2 \\ \\ A=40m^2$

Finally:

<em>The shaded region has an area of 40 square meters</em>

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4 years ago

Ursula is making treasure boxes for campers. There are 12 younger campers, and each of their boxes contains 4 prizes. There are

sdas [7]

There are 12 younger campers, and each of their boxes contains 4 prizes. There are 10 older campers, and each of their boxes contains 6 prizes. That will be 48 + 60 = 108 prizes.

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3 years ago

A small craft in lake Ontario sends out a distances signal. The coordinates of the boat in trouble are (57,64). One rescue boat

KatRina [158]

Answer:

The coast guard craft will get to the distressed boat the fastest.

Step-by-step explanation:

The coordinates of boat are (57,64).

The coordinates of rescue boat are (67,83).

The coordinates of coast guard craft are (65,46).

Both rescue crafts travel at the same rate. One of them will get to the distressed boat the faster, whose distance from the boat is least.

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The distance between boat and rescue boat is

$d_1=\sqrt{(67-57)^2+(83-64)^2}=21.4709105536\approx 21.47$

The distance between boat and coast guard craft is

$d_2=\sqrt{(65-57)^2+(46-64)^2}=19.6977156036\approx 19.70$

Since the distance between boat and coast guard craft is least, therefore coast guard craft will get to the distressed boat the fastest.

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3 years ago