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Fittoniya [83]
3 years ago
15

Suppose the average price of gasoline for a city in the United States follows a continuous uniform distribution with a lower bou

nd of $3.50 per gallon and an upper bound of $3.80 per gallon. What is the probability a randomly chosen gas station charges less than $3.70 per gallon?
Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

And for this case we can write the probability like this:

P(X

And then the final answer for this case would be \frac{2}{3}=0.667

Step-by-step explanation:

For this case we define our random variable X "price of gasoline for a city in the USA" and we know the distribution is given by:

X \sim Unif (a=3.5, b=3.8)

And for this case the density function is given by:

f(x) = \frac{x}{b-a}= \frac{x}{3.8-3.5}=, 3.5 \leq X \leq 3.8

And we want to calculate the following probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

And for this case we can write the probability like this:

P(X

And then the final answer for this case would be \frac{2}{3}=0.667

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Answer:

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Difference of 2 squares:  256x^4 - 49x^2.

GCF:  4x^2 - 24x + 144.

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Factoring Trinomial: b^2 + 5b - 36.

Step-by-step explanation:

1.  x^2 + 17x - 30 will not factor.

2.  256x^4 - 49x^2 = (16x^2 + 7x)(16x^2 - 7x)

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