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gizmo_the_mogwai [7]
3 years ago
12

If you were to take a cross section parallel to the base of one of the holding tanks, how would you describe the shape?

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
8 0

it would be a rectangle

hope this helps :)

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4(2+3c)=56<br>how woud i solve this Multi-step equation sow with all
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Calculate S58 for the arithmetic sequence {an}= {5/6n+1/3} If you could show me the steps that would be great. I keep following
Amanda [17]

Answer is 8671/6 which is the third choice

===================================

Work Shown:

Find the first term of the sequence by plugging in n = 1

a_n = (5/6)*n + 1/3

a_1 = (5/6)*1 + 1/3    replace n with 1

a_1 = 5/6 + 1/3

a_1 = 5/6 + 2/6

a_1 = 7/6

Repeat for n = 58 to get the 58th term

a_n = (5/6)*n + 1/3

a_58 = (5/6)*58 + 1/3    replace n with 58

a_58 = (5/6)*(58/1) + 1/3

a_58 = (5*58)/(6*1) + 1/3

a_58 = 290/6 + 1/3

a_58 = 145/3 + 1/3

a_58 = 146/3

Now we can use the s_n formula below with n = 58

s_n = (n/2)*(a_1 + a_n)

s_58 = (58/2)*(a_1 + a_58)    replace n with 58

s_58 = (58/2)*(7/6 + a_58)   replace a_1 with 7/6

s_58 = (58/2)*(7/6 + 146/3)   replace a_58 with 146/3

s_58 = (58/2)*(7/6 + 292/6)

s_58 = (58/2)*(299/6)

s_58 = (58*299)/(2*6)

s_58 = 17342/12

s_58 = 8671/6


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2 years ago
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Answer:

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Step-by-step explanation:

n (n + 1) = 2550

n^2 + n = 2550

n = 50

n + 1 = 51

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1 and 1/2 
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3 years ago
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Answer:

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Step-by-step explanation:

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