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zhenek [66]
2 years ago
5

Help me!!! I need help ASAP

Mathematics
1 answer:
tia_tia [17]2 years ago
8 0

9514 1404 393

Answer:

  y = 3.02x^3 -5.36x^2 +5.68x +8.66

Step-by-step explanation:

Your graphing calculator (or other regression tool) can solve this about as quickly as you can enter the numbers. If you have a number of regression formulas to work out, it is a good idea to become familiar with at least one tool for doing so.

__

If you're trying to do this by hand, the x- and y-values give you 4 equations in the 4 unknown coefficients.

  a·1^3 +b·1^2 +c·1 +d = 12

  a·3^3 +b·3^2 +c·3 +d = 59

  a·6^3 +b·6^2 +c·6 +d = 502

  a·8^3 +b·8^2 +c·8 +d = 1257

Solving this by elimination, substitution, or matrix methods is tedious, but not impossible. Calculators and web sites can help. The solutions are a = 317/105, b = -75/14, c = 1193/210, d = 303/35. Approximations to these values are shown above.

You might be interested in
Three more than a number is 15
podryga [215]

Answer:

The number is 12

Step-by-step explanation:

If 15 is three more than the number is three less so you do, 15 - 3 which is 12.

I hope this helps

7 0
2 years ago
Translate<br> Solve the equation.<br> 3m= 5(m + 3)-3<br> HELP
kvasek [131]

Answer:

m = -6

Step-by-step explanation:

3m= 5(m + 3)-3

Distribute

3m = 5m +15 -3

Combine like terms

3m = 5m +12

Subtract 5m

3m-5m = 5m+12-5m

-2m = 12

Divide by -2

-2m/-2 = 12/-2

m = -6

7 0
3 years ago
A student committee is to consist of 2 freshmen, 5 sophomores, 4 juniors, and 3 seniors. If 6 freshmen, 13 sophomores, 8 juniors
mezya [45]
<h3>Answer:  491,891,400</h3>

Delete the commas if necessary.

============================================================

Explanation:

There are 6 freshmen total and we want to pick 2 of them, where order doesn't matter. The reason it doesn't matter is because each seat on the committee is the same. No member outranks any other. If the positions were labeled "president", "vice president", "secretary", etc, then the order would matter.

Plug n = 6 and r = 2 into the nCr combination formula below

n C r = \frac{n!}{r!(n-r)!}\\\\6 C 2 = \frac{6!}{2!*(6-2)!}\\\\6 C 2 = \frac{6!}{2!*4!}\\\\6 C 2 = \frac{6*5*4!}{2!*4!}\\\\ 6 C 2 = \frac{6*5}{2!}\\\\ 6 C 2 = \frac{6*5}{2*1}\\\\ 6 C 2 = \frac{30}{2}\\\\ 6 C 2 = 15\\\\

This tells us there are 15 ways to pick the 2 freshmen from a pool of 6 total.

Repeat those steps for the other grade levels.

n = 13 sophomores, r = 5 selections leads to nCr = 13C5 = 1287. This is the number of ways to pick the sophomores.

You would follow the same type of steps shown above to get 1287. Let me know if you need to see these steps.

Similarly, 8C4 = 70 is the number of ways to pick the juniors.

Lastly, 14C3 = 364 is the number of ways to pick the seniors.

-----------------------------

To recap, we have...

  • 15 ways to pick the freshmen
  • 1287 ways to pick the sophomores
  • 70 ways to pick the juniors
  • 364 ways to pick the seniors

Multiply out those values to get to the final answer.

15*1287*70*364 = 491,891,400

This massive number is a little under 492 million.

7 0
2 years ago
Solve 2x-3&lt; 2<br>please answer it fast ​
murzikaleks [220]

Answer:

x<5/2

Step-by-step explanation:

We have

2x−3<2

Add 3 to both sides.

2x−3 +3 <2 +3

which makes

2x<5

Divide both sides by 2.

2x/2 < 5/2

x<5/2

4 0
2 years ago
A square on a coordinate plane has the points A(0, 0), B(0, 5), C(5, 5) and D(5, 0). If Square ABCD is rotated about the origin
Georgia [21]

Answer:

B. 5 units

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, dilation, rotation or translation.

If a point X(x,y) is rotated about the origin 180 degrees clockwise the new point is at X'(-x, -y).

If the square with vertices at A(0, 0), B(0, 5), C(5, 5) and D(5, 0) is rotated about the origin 180 degrees clockwise the new points are at A'(0, 0), B'(0, -5), C'(-5, -5), D'(-5, 0)

A square has four equal sides. The distance between two points X(x_1,y_1)\ and\ Y(x_2,y_2) is:

|XY|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Hence:

|A'B'|=\sqrt{(0-0)^2+(-5-0)^2} =5

3 0
3 years ago
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