For the equation F(x) = ax² + bx + c we have:
- maximum value if a<0
- minimum value if a>0
F(x) = -3x² + 18x + 3 ⇒ a = -3, b = 18
a < 0 ⇒ the function has a maximum value
Quadratic function has the maximum value (or minimum) at vertex of its parabola.
The maximum value is k at x=h where: 
and k = F(h)
Therefore:
<h3>
The function has a maximum value of 30 at x = 3</h3>
Answer:
The perimeter is 6x+8
Step-by-step explanation:
2(2x+3) +2(x+1)
4x+6+2x+2
6x+8
Answer:
(x, y) ⟶ (x + 4, y + 2)
Step-by-step explanation:
If you shift a point four units to the right, x ⟶ x + 4.
If you shift it up two units, y ⟶ y + 2.
If you combine the two shifts into one transformation, the rule becomes
(x, y) ⟶ (x + 4, y + 2)
Multiplying a - and a + equals a - , -8r18
