The y-intercept in the linear equation −2y−4x−6=0 is _[blank]_. will give brainliest

Mathematics

2 answers:

Ronch [10]3 years ago

7 0

Answer:

-3 is the value of the location where the line crosses the y-axis,and is commonly referred in the slope-intercept form of a line "the intercept". Now it may be your teacher expects you to answer this as the point on the plane where the y-intercept occurs, and that should be the point (0, -3). Make sure you follow your teacher's notation.

Step-by-step explanation:

Re-write the equation given in slope=intercept form by isolating the variable "y" on one side of the equation and expressing the rest in slope*x + y-intercet form:

$-2y-4x-6=0\\-4x-6=2y\\y=-2x-3\\$

which tells us that the slope of the line is -2 and it y-intercept is "-3".

Now, watch out because you may be asked to write the actual coordinates of the y-intercept, which are: (0, -3)

giving the x-coordinate 0 and the y-value where the line crosses the y-axis.

irga5000 [103]3 years ago

5 0

Answer:

-3.

Step-by-step explanation:

-2y - 4x - 6 = 0

-2y = 4x + 6

y = -2x - 3

So, the y-intercept is (0, -3).

Hope this helps!

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Oksana_A [137]

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3 years ago

According to the last census (2010), the mean number of people per household in the United States is LaTeX: \mu = 2.58 Assume a

Veseljchak [2.6K]

Answer:

P(2.50 < Xbar < 2.66) = 0.046

Step-by-step explanation:

We are given that Population Mean, $\mu$ = 2.58 and Standard deviation, $\sigma$ = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar $\leq$ 2.50)

P(Xbar < 2.66) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z < -1.68) = 1 - P(Z 1.68)

= 1 - 0.95352 = 0.04648

P(Xbar $\leq$ 2.50) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{2.50-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z $\leq$ -3.92) = 1 - P(Z < 3.92)