Sorry I need the 2 answers to ask my own. I wouldn’t of understood this wnywyas. Hopefully you find someone who can do it
Answer:
D
Step-by-step explanation:
To obtain vertex form from the given equation use the method of completing the square
given 8y + x² = - y² - 181 + 26x
rearrange having the x terms and y terms together
add y² to both sides
8y + x² + y² = - 181 + 26x ( subtract 26x from both sides )
x² - 26x + y² + 8y = - 181
add (half the coefficient of the x/y terms )² to both sides
x² + 2(- 13)x + 169 +y² + 2(4)y + 16 = - 181 + 169 + 16
completing the square on both the x and y terms
(x - 13)² + (y + 4)² = 4 → D
Area of a square = Side × Side
Side = 7x-3
Area of the square = (7x-3) × (7x-3)
= 7x(7x-3) -3(7x-3)
= 49x^2 -21x -21x +9
=49x^2 -42x +9
I have no clue what this answer is but I hope you find it out
Answer:
The value of A is 5
Step-by-step explanation:
- The number is divisible by 3 if the sum of its digits is a number
divisible by 3
- Ex: 126 is divisible by 3 because the sum of its digits = 1 + 2 + 3 = 6
and 6 is divisible by 3
- The number is divisible by 5 if its ones digit is zero or 5
- Ex: 675 is divisible by 5 because its ones digit is 5
890 is divisible by 5 because its ones digit is 0
- We are looking for the value of A in the 4-digit number 3A5A which
makes the number divisible by both 3 and 5
∵ A is in the ones position
∴ A must be zero or 5
- Let us try A = 0
∵ A = 0
∴ The number is 3050
∵ The sum of the digits of the number = 3 + 0 + 5 + 0 = 8
∵ 8 is not divisible by 3
∴ 3050 is not divisible by both 3 and 5
∴ A can not be zero
- Let us try A = 5
∵ A = 5
∴ The number is 3555
∵ The sum of the digits of the number = 3 + 5 + 5 + 5 = 18
∵ 18 is divisible by 3
∴ 3555 is divisible by both 3 and 5
∴ A must be equal 5
* <em>The value of A is 5</em>
