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andreyandreev [35.5K]
3 years ago
12

Part A: Consider the equation x + 7 = 16. Which number from the set {5, 7, 9, 11} makes the equation true?

Mathematics
1 answer:
wel3 years ago
3 0

Part A: Substitute/plug in each number into the equation to see which number will make the equation true.

x + 7 = 16      Plug in 5 into "x"

5 + 7 = 16

12 = 16    5 doesn't make the equation true because it equals 12 not 16

x + 7 = 16     Plug in 7 into "x"

7 + 7 = 16

14 = 16     7 doesn't make the equation true because it equals 14 not 16

x + 7 = 16     Plug in 9 into "x"

9 + 7 = 16

16 = 16             9 makes the equation true because it equals 16

Part B: Plug in 9 into "x" in the inequality to see if it still makes it true.

x + 7 < 16     [x plus 7 is less than 16]

9 + 7 < 16

16 < 16     [16 is less than 16]  The same number would not make the inequality true because 16 can't be less than itself.

To figure out which numbers satisfy the inequality, plug it into the inequality:

x + 7 < 16      Plug in 5 into "x"

5 + 7 < 16

12 < 16      5 does satisfy the inequality because 12 is less than 16

x + 7 < 16     Plug in 7 into "x"

14 < 16     7 does satisfy the inequality because 14 is less than 16

x + 7 < 16     Plug in 11 into "x"

11 + 7 < 16

18 < 16     11 doesn't satisfy the inequality because 18 isn't less than 16

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Answer and Step-by-step explanation:

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X + y = 14

And the sum of square of this number is:

f = x2 + y2

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Differentiate with respect to x, we get:

F’(x) = [ x2 + (14 – x)2]’ = 0

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Hence the sum of squares of these numbers is minimum when x = y = 7

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