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kirill [66]
3 years ago
6

5(x+3)-7(6-3)+29=50-3(8-x)

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0

Answer:

\quad x=\frac{3}{2}

Step-by-step explanation:

7\left(6-3\right)=21, \mathrm{Expand\:}5\left(x+3\right)-21+29:\quad5x+23, \mathrm{Expand\:}50-3\left(8-x\right):\quad 3x+26, Subtract 23 and 3x from both sides and simplify: 2x=3, Divide both sides by 2 and simplify: x=\frac{3}{2}

<em>Hope this helps!!!</em>

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Answer:

26

Step-by-step explanation:

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3 years ago
Find the domain and range of the exponential function h(x) = 125x.
kirill [66]
H(x) = 125^x

Domain: all the real numbers (from negative infinity to infinity)

Range: all the positive real numbers.

As x decreases 125^x decreases approaching to 0. The function will never reach the value 0 but will approximate to it as x goes to negative infinity. The rate of decreasing gets lower and lower, with a limit of zero, when x becomes more and more negative.

As x increases 125^x increases indefinetely and at an increasing rate. That means that the increase is accelerated (the bigger the value of x the bigger the rate of increasing).
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3 years ago
the diameter D of a sphere is 13m calculate the sphere volume V use the value 3.14 round your answer to the nearest tenth
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Answer:

1149.8 m³

Step-by-step explanation:

The volume (V) of a sphere is calculated as

V = \frac{4}{3}πr³ ( r is the radius )

Here diameter = 13, thus radius = 13 ÷ 2 = 6.5

V = \frac{4}{3} × 3.14 × 6.5³

   = \frac{4}{3} × 3.14 × 274.625

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5 0
3 years ago
Ms. Thomas buys 3 pounds of sliced ham to make sandwiches. It takes 1 3 lb of ham for each sandwich. How many ham sandwiches can
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Answer:

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Step-by-step explanation:

we know that

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Read 2 more answers
The following data represent the weights in pounds of a sample of 25 police officers:
DochEvi [55]

Given:

The data values are:

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, and 171.

To find;

a. Lower quartile.

b. Upper quartile.

c. Interquartile range.

Solution:

We have,

164, 148, 137, 157, 173, 156, 177, 172, 169, 165, 145, 168, 163, 162, 174, 152, 156, 168, 154, 151, 174, 146, 134, 140, 171.

Arrange the data values in ascending order.

134, 137, 140, 145, 146, 148, 151, 152, 154, 156, 156, 157, 162, 163, 164, 165, 168, 168, 169, 171, 172, 173, 174, 174, 177.

Divide the data values in two equal parts.

(134, 137, 140, 145, 146, 148, 151, 152, 154, 156, 156, 157), 162, (163, 164, 165, 168, 168, 169, 171, 172, 173, 174, 174, 177)

Divide each parentheses in two equal parts.

(134, 137, 140, 145, 146, 148), (151, 152, 154, 156, 156, 157), 162, (163, 164, 165, 168, 168, 169), (171, 172, 173, 174, 174, 177)

a. Location of lower quartile is:

Q_1=\dfrac{1}{4}(n+1)\text{th term}

Q_1=\dfrac{1}{4}(25+1)\text{th term}

Q_1=\dfrac{26}{4}\text{th term}

Q_1=6.5\text{th term}

The lower quartile of the weights is:

Q_1=\dfrac{148+151}{2}

Q_1=\dfrac{299}{2}

Q_1=149.5

Therefore, the location of the lower quartile of the weights is between 6th term and the 7th term. The value of the lower quartile is 149.5.

b. Location of upper quartile is:

Q_3=\dfrac{3}{4}(n+1)\text{th term}

Q_3=\dfrac{3}{4}(25+1)\text{th term}

Q_3=\dfrac{3\cdot 26}{4}\text{th term}

Q_3=19.5\text{th term}

The upper quartile of the weights is:

Q_3=\dfrac{169+171}{2}

Q_3=\dfrac{340}{2}

Q_3=170

Therefore, the location of the upper quartile of the weights is between 19th term and the 20th term. The value of the upper quartile is 170.

c. The interquartile range of the given data set is:

IQR=Q_3-Q_1

IQR=170-149.5

IQR=20.5

Therefore, the interquartile range of the weights is 20.5.

7 0
3 years ago
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