How many solutions does a system of equations have when solving results in the statement 3=5
2 answers:
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Answer:
C
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
The square on the hypotenuse is equal to the sum of the squares on the 2 other sides, that is
x² + 6² = 17²
x² + 36 = 289 ( subtract 36 from both sides )
x² = 253 ( take the square root of both sides )
x = → C
Since ABC is equilateral, all 3 sides have equal length. side AC is 8 units since side BC is 8 units.
Line BD is placed in the middle, making D the midpoint of side AC.
knowing this information we can determine that the length of DC is 4 units (half of AC)
since triangle BDC is a right triangle, we can use the side lengths in the pythagorean theorem to find the length of BD
a²+b²=c² where a & b = legs of triangle , and c= hypotenuse (longest side)
we are given the hypotenuse and found one leg so we can plug our values into the equation to find the third
4² + b²= 8²
16 + b² = 64
b² = 48
b =
b= 4√3 or about 6.928 units
hope this helped