<span>Circle D circumscribes ABC and ABE, The statements that best describe the triangles are:
</span><span>Statement I: The perpendicular bisectors of ABC intersect at the same point as those of ABE.
Statement II: The distance from C to D is the same as the distance from D to E. Hence, each of them (CD and DE) is a radius of the given circle.
So, the answer is the second option, I and II.
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<h3>
Answer: 16 square units</h3>
Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5
a^2 + b^2 = c^2
3^2 + x^2 = 5^2
9 + x^2 = 25
x^2 = 25-9
x^2 = 16
x = sqrt(16)
x = 4
This is a 3-4-5 right triangle.
The height of the parallelogram is 4 units.
We have enough info to find the area of the parallelogram
Area of parallelogram = base*height
Area of parallelogram = 4*4
Area of parallelogram = 16 square units
Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.
Answer:
you cant solve for x but
55x/11x=5x
Step-by-step explanation:
300.02 if you use the square root of 72
Add 2 to 3 and then your answer is x>5
