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Nady [450]
3 years ago
6

Alicia says that 6÷2+5 is the same as 5+6÷2. is Alicia correct or incorrect

Mathematics
2 answers:
Dominik [7]3 years ago
6 0
She is correct, as long as you don't move the symbols around, you will always get the same answer. Because of Order of Operations. Try it.

6/2+5

3+5=8

then,

5+6/2

5+3=8

This means that Alicia is correct.

As long as you don't switch the symbols around.
Example: 6+2/5 or switch numbers around 6/5+2.
liq [111]3 years ago
3 0
It is not correct because of the order the problem is organized in.
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A computer can be classified as either cutting dash edge or ancient. Suppose that 86​% of computers are classified as ancient. ​
Leno4ka [110]

Answer:

(a) The probability that both computers are ancient is 0.7396

(b) The probability that all seven computers are ancient is 0.3479

(c) The probability that at least one of seven randomly selected computers is cutting dash edge is 0.6520.

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

Step-by-step explanation:

We know that 86​% of computers are classified as ancient. This means, if one computer is chosen at random, there is an 86% chance that it will be classified as ancient.

P(ancient)=0.86

(a) To find the probability that two computers are chosen at random and both are ancient​ you must,

The probability that the first computer is ancient is P(ancient)=0.86 and the probability that the second computer is ancient is P(ancient)=0.86

These events are independent; the selection of one computer does not affect the selection of another computer.

When calculating the probability that multiple independent events will all occur, the probabilities are multiplied, this is known as the rule of product.

Let A be the event "the first computer is ancient" and B the event "the second computer is ancient".

P(A\:and \:B)=P(A)\cdot P(B)=0.86\cdot 0.86=0.86^2= 0.7396

(b) To find the probability that seven computers are chosen at random and all are ancient​ you must,

Following the same logic in part (a) we have

Let A be the event "the first computer is ancient",

B the event "the second computer is ancient",

C the event "the third computer is ancient",

D the event "the fourth computer is ancient",

E the event "the fifth computer is ancient",

F the event "the sixth computer is ancient", and

G the event "the seventh computer is ancient"

P(A\:and \:B\:and \:C\:and \:D\:and \:E\:and \:F\:and \:G)=\\P(A)\cdot P(B)\cdot P(C)\cdot P(D)\cdot P(E)\cdot P(F)\cdot P(G) =(0.86)^7=0.3479

(c) To find the probability that at least one of seven randomly selected computers is cutting dash edge​ you must

Use the concept of complement. The complement of an event is the subset of outcomes in the sample space that are not in the event.

Let C the event "the computer is cutting dash edge".

Let A the event "the seven computers are ancient".

P(C)=1-P(A)=1-0.3479=0.6520

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

5 0
3 years ago
What's 99*pi*2234/2233+0.0001. Correct get 100 points
Brut [27]
I believe the answer is 311.157055138. That is if i did my math correctly. I hope this helps. Good luck!
3 0
3 years ago
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jim sat at a table with 4 teachers and 9 children how many people were at the table after jim sat down​
xeze [42]

Answer:

Step-by-step explanation:

Both teachers and children are people.  If there were 4 teachers and 9 children already at the table, sitting down, when Jim arrived, then that would be 13 people at the table before he sit and 14 people after he sits.

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What is a GCF of 10 and 20
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The greatest common factor of 10 and 20 is 10.

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Solve the simultaneous equations by substitution<br> 4x+3y=-2<br> 3y=4-x
stiv31 [10]

Answer: x=-2 y=2

Step-by-step explanation:

I decided that isolating the y value of the second equation is the best way to start solving.

I divide 3 from both sides to get y= (4-x)/3. With this, I can substitute into the first equation. 4x+3(4-x)/3)=-2.

The multiplying the 3 by the denominator three cancels each other out to make:

4x+4-x=-2.

We subtract 4 on both sides and then subtract x from 4x.

We end up with 3x=-6. Then, we divide both sides by 3.

x=-2.

Now we substitute this into the second equation to solve.

3y=4-(-2)

This becomes 3y=4+2 which is 3y=6

We divide both sides by 3 to get y=2

We end up with x=-2 and y=2.

I hope you learned something :)

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