Your welcome! 3.66 is your right answer!
Answer:
0.60
Step-by-step explanation:
In the category of pets
22 students had a cat = P(C)
17 students had a dog = P(D)
9 students had both a dog and a cat = P(C and D)
The formula to find the Probability of two events =
P(C or D) = P(C) + P(D) - P(C and D)
P(cat or dog) = P(cat) + P( dog) - P(cat and dog)
P(cat or dog) = 22/50 + 17/50 - 9/50
P(cat or dog) = 0.44 + 0.34 - 0.18
P(cat or dog) = 0.60
The probability the student will have a dog or a cat is 0.60
I can’t really see the answer choices
Area = length (L) * Width (W)
Perimeter = (2*L) + (2*W)
L*W = 35
W = 35/L
2L + 2W = 27
L+W = 13.5
L + 35/L = 13.5
L^2 + 35 = 13.5L
L^2 - 13.5L + 35 = 0
(L - 10) (L - 3.5) = 0
L = 10 ft or L = 3.5 ft
LW = 35
If L = 10 ft
W = 3.5 ft