Answer:
15 kilometers
Step-by-step explanation:
So we know:
For 4 days she runs 1500 meters each day.
For 3 days she runs 3 kilometers each day.
First off, lets convert 1500 meters into kilometers.
There are 1000 meters in a kilometer, so pluggin in 1500 meters:
1500/1000 = 1.5
So for 4 days she runs 1.5 kilometers each day.
Now, to find the total kilometers, we must find multiply the 1.5 kilometers by the 4 days, the 3 kilometers by the 3 days, then add those two together.
So lets do this:
1.5*4 = 6
So she ran 6 kilometers in the first 4 days.
Next we have:
3*3 = 9
So she ran 9 kilometers in the last 3 days.
Now finally add them together:
6 + 9 = 15
So she ran a total of 15 kilometers.
Hope this helps!
The range of set B is approximately the range of set A
Answer:
the 4th option is correct
Step-by-step explanation:
Original expression
Split up the exponent
![x(\sqrt[9]{y^{2} } )](https://tex.z-dn.net/?f=x%28%5Csqrt%5B9%5D%7By%5E%7B2%7D%20%7D%20%29)
The 1/9 of an expression is the same thing is the 9th root of the expression.
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.
