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3 years ago

An organism that has the ability to maintain an internal temperature suitable for life

Biology

1 answer:

Andreyy893 years ago

8 0

Answer:

When any living organism gets thrown off balance, its body or cells help it return to normal. In other words, living organisms have the ability to keep a stable internal environment. Maintaining a balance inside the body or cells of organisms is known as homeostasis. mark me as the brainliest

Explanation:

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Contrast mitosis and cytokinesis

lyudmila [28]

Answer:

why

Explanation:

8 0

2 years ago

When would a female have a 100% chance of inheriting a sex-linked trait?

Vladimir79 [104]

Answer:

Explanation: Well C is usually correct for everything

3 0

3 years ago

if an element has a half-life of 30 million years and there is 12.5% of it remaining in a rock, how old is that rock

Assoli18 [71]

Answer:

The half-life of a substance is the amount of time it takes for half of that substance to decay. However, after two half-lives, half of the half remaining will decay, leaving you with one quarter of the original substance.

So, after 1 million years you will have 50% of the original substance remaining.

And, after 2 million years you will have 25% of the original substance remaining.

After 3 million years you will have 12.5% of the original substance remaining.

And after 4 million years you will have 6.25% of the original substance remaining.

Explanation:

Hope it helps:)

3 0

3 years ago

When a living organism dies, it stops taking in new carbon. Thus, as the radioactive carbon-14 decays, the ratio of carbon-12 to

Alexxandr [17]

Answer: The fossil is 11459 years old.

Explanation:

Half-life of carbon-14 = 5700 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{5700\text{years}}$

$k=1.21\times 10^{-4}\text{years}^{-1}$

Now we have to calculate the age of the sample:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}\text{years}^{-1}
t = age of sample = ?
a = let initial amount of the reactant = 100 g
x = amount decayed = 75 g
a - x = amount left after decay process = 100 - 75 = 25 g Now put all the given values in above equation, we get
[tex]t==\frac{2.303}{1.21\times 10^{-4}}\log\frac{100}{25}$

$t=11459years$

The fossil is 11459 years old.

4 0

2 years ago

The area between Z lines is the

Nataly_w [17]

Answer:

Sarcomere

Explanation:

A myofibril or muscle fiber under an electron microscope shows alternate light band and dark bands. These bands give the skeletal muscle and cardiac muscle a striated appearance. The light band is called the I- band or isotropic band, and the dark band is known as A- band or anisotropic band. In the center of the I-band Z-line is present. It is discovered from a German term Zwischenscheibe (between the disc). The portion of myofibril between one Z-line to the next Z-line is called sarcomere.

3 0

3 years ago