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Darya [45]
3 years ago
7

Given that tan^2 theta=3/8, what is the value of sec theta?

Mathematics
2 answers:
jasenka [17]3 years ago
6 0
Work shown above! Answer is √(11/8)

AleksandrR [38]3 years ago
4 0

Answer:

Its B. +- sqrt11/8 on ed

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Wade and Alexandra are 240 feet apart when they start walking toward one another. Alexandra walks twice as fast as Wade so whene
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Answer:

The initial distance between Wade and Alexandra is 240ft.

They walk towards each other.

Alexandra walks twice as fast as Wade.

Now, because they are walking towards each other, when the distance walked by both of them equals 240 ft, they will meet.

Then:

if Wade walks z ft, Alexandra walks 2*z ft.

So we have the equation:

Distance that Wade walked + Distance that Alexandra walked = 240ft

z + 2*z = 240ft

3*z = 240ft

z = 240ft/3 = 80ft

They will meet when Wade walks 80ft.

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D. 60 divided by h.

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What is the answer to this question I can’t work it out Ni=n02(yi-yo)/t2
mr_godi [17]

Changing the subject of an equation involves solving for another variable in the equation

The equation of t is t=\frac{\sqrt{y_i-y_o}}{N}

<h3>How to change the subject of the equation</h3>

The equation is given as:

N=\sqrt[2]{\frac{y_i-y_o}{t^2}}

Rewrite the equation as:

N=\sqrt{\frac{y_i-y_o}{t^2}}

Evaluate the square root of t^2

N=\frac{\sqrt{y_i-y_o}}{t}

Multiply both sides by t

Nt=\sqrt{y_i-y_o}

Make t the subject, in the above equation

t=\frac{\sqrt{y_i-y_o}}{N}

Hence, the equation of t is t=\frac{\sqrt{y_i-y_o}}{N}

Read more about subject of formula at:

brainly.com/question/657646

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2 years ago
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dezoksy [38]
All -1.8

In addition and subtraction the order of the numbers does not matter, so the result will always remain the same
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