The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
volume of the box is 675 cubic inches
A machine produces open boxes using square sheets of plastic.
It is a square sheet so length and width are same
Lets assume length as x so width is also x
The machine cuts equal-sized squares measuring 3 inches on a side from each corner of the sheet.
After turning up the sides the height of the box becomes 3 inches
We know the volume of a box formula
Volume = Length * width * height
We know length is x , width is x and height = 3
So V = x * x * 3
Given volume = 675 cubic inches
Divide by 3 on both sides
Now we take square root on both sides
x = 15
the length of one side of the open box is 15 inches.
Answer:
Step-by-step explanation:
The figure B is the scaled copy of the figure A.
The both figures are similar to each other.
<u>The scale factor is the ratio of corresponding sides of figure B to A:</u>
or
Answer:
2 pages per minute
Step-by-step explanation:
when you divide 7 by 3, your answer would be 2.3333333333 and so on.
however, you can say
iT pRiNtS 2 aNd A tHiRd pAgEs PeR MiNuTe.
you should say it prints 2 whole pages a minute.
i hope this helps!
stay safe!
:)
Answer:
step 3: he should have divided both sides by -7
