Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Add 5ft 7in and 4ft 8in together
5ft 7in + 4ft 8in = 10ft 3in
Answer:
hola a la par y me dijo dígame qué hora prefieres que te hace falta un poco pero no me e sentido así
Step-by-step explanation:
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Answer:
This question is incomplete
The ratio of the distance between the foci and the length of the <em>major</em> axis is called eccentricity.
<h3>
Definitions of dimensions in ellipses</h3>
Dimensionally speaking, an ellipse is characterized by three variables:
- Length of the <em>major</em> semiaxis (
). - Length of the <em>minor</em> semiaxis (
). - Distance between the foci and the center of the ellipse (
).
And there is the following relationship:
(1)
Another variable that measure how "similar" is an ellipse to a circle is the eccentricity (
), which is defined by the following formula:
,
(2)
The greater the eccentricity, the more similar the ellipse to a circle.
Therefore, the ratio of the distance between the foci and the length of the <em>major</em> axis is called eccentricity. 
To learn more on ellipses, we kindly invite to check this verified question: brainly.com/question/19507943